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3 years ago

Rename 200 tens into hundreds

Mathematics

1 answer:

Arlecino [84]3 years ago

4 0

2 hundreds be cause there are 2, and you are trying to find hundreths so take the first number

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What is 3/36 simplified(3/36 is a fraction

Galina-37 [17]

3/36 simplified equals 1/12

5 0

3 years ago

Read 2 more answers

The ratio of students who wear glasses to the total class is 2:5

Taya2010 [7]

Answer:

a. 2:3, b. 25 students, c. 3:2

Step-by-step explanation:

a. 5 (total) - 2 (with glasses) = 3 (without glasses), making the ratio 2:3.

b. We can assign the total students with the variable x. 3:5=15:x, 75=3x, x=25. 25 total students.

c. 25 (total students) - 15 (without glasses) = 10 (with glasses). (10+5):(15-5) is 15:10, which, when simplified, equals to 3:2.

4 0

2 years ago

A right circular cylinder has a base radius of 56 mm and a height of 128 mm. What is its volume in cubic centimeters? Round the

anzhelika [568]

Answer:

V = 1261 mm2

Step-by-step explanation:

Hello

V = Pi*(r^2)*h

V = Pi*([56]^2)*(128=

V = 1261 mm2

Best regards

4 0

3 years ago

Peter's salary is twice Anne's salary and half of David's salary. Then the average salary of Anne and David is _ of Peter's sala

satela [25.4K]

<h3><u>Answer:</u></h3>

Average of salary of Anne and David is 1.25 of Peter's Salary

<h3><u>Explanation:</u></h3>

In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.

Let us assume Peter's Salary as P.

Then we can calculate Anne's salary A = $\frac{P}{2}$ .

Also David's salary = D = $2 \times P$

Average of Anne's and David's salary = $\frac{A+D}{2}$

Average of Anne's and David's salary = $\frac{\frac{P}{2} + 2 \times P}{2}$

Average of Anne's and David's salary = $\frac{5 \times P}{4}$

Average = 1.25 \times P

6 0

3 years ago

What is the measure of arc WXY

bonufazy [111]

Answer:

152°

Step-by-step explanation:

Let P be any point on tangent $\overleftrightarrow{YZ}$ and WY is secant or chord of the $\odot J$ .

$\therefore m\angle WYZ + m\angle WYP = 180°\\(Straight \: line \: \angle 's) \\\therefore 104° + m\angle WYP = 180°\\\therefore m\angle WYP = 180°- 104° \\\red{\boxed {\bold {\therefore m\angle WYP = 76°}}} \\$

NOW, by tangent secant theorem:

$m\angle WYP =\frac{1}{2}\times m(\widehat{WXY}) \\\\76°=\frac{1}{2}\times m( \widehat{WXY}) \\\\76°\times 2 =m( \widehat{WXY}) \\\huge \purple {\boxed {\therefore m(\widehat{WXY}) = 152°}}$

8 0

3 years ago