First, you gotta simplify. There’s really nothing to simplify so just take it out of the parenthesis.
2x-8=2x-4
Now turn the -8 into a +8. Add it on each side.
2x=2x+8
Now turn the 2x on the right into a negative. Do the same thing you did with the 8.
Now it’s:
0 = 8
That means there’s no solution.
Hope this helped :)
Answer: B. y-1=2(x-3)
Step-by-step explanation:
First subtract both sides by 2x so it becomes -y=-2x-1
Second divide both sides by -1 so it becomes y=2x+1
After that to get it in the form they want it subtract 1 from both sides so that it becomes y-1=2x
Each of these roots can be expressed as a binomial:
(x+1)=0, which solves to -1
(x-3)=0, which solves to 3
(x-3i)=0 which solves to 3i
(x+3i)=0, which solves to -3i
There are four roots, so our final equation will have x^4 as the least degree
Multiply them together. I'll multiply the i binomials first:
(x-3i)(x+3i) = x²+3ix-3ix-9i²
x²-9i²
x²+9 [since i²=-1]
Now I'll multiply the first two binomials together:
(x+1)(x-3) = x²-3x+x-3
x²-2x-3
Lastly, we'll multiply the two derived terms together:
(x²+9)(x²-2x-3) [from the binomial, I'll distribute the first term, then the second term, and I'll stack them so we can simply add like terms together]
x^4 -2x³-3x²
<u> +9x²-18x-27</u>
x^4-2x³+6x²-18x-27
Answer:
The answer is A.
Step-by-step explanation:
It's to much , sorry.
