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Rudik [331]
3 years ago
9

a 4 by 5 inch photo is enlarged by multiplying every dimension by 2 to form a similar 8 by 10 inch photo. What is the ratio of t

he perimeter of the smaller rectangle to that of the larger? What is the ratio of the two areas?
Mathematics
1 answer:
dimaraw [331]3 years ago
3 0
Although you could do it by calculating he ratios and areas, then comparing, there’s an easier way:
If every dimension is multiplied by two, every side length must also be multiplied by two, so the perimeter is doubled.
If every dimension is doubled, the new image must be both twice as wide and twice as tall as the original. Being twice as wide means having double the area, and so does being twice as tall. If these effects are combined, we conclude the area has increased by a factor of four.
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If a tellemarketer made 200 phone calls and 35 customers signed up what is the relative frequency of getting a customer and not
Snezhnost [94]

Answer:

82.5% and 17.5%

Step-by-step explanation:

The telemarketer made 200 phone calls and only 35 people signed up. Therefore, we need to find the amount of people who didnt.

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This meants that the frequency of getting a customer is 35/200 and not is 165/200. In percentages,

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6 0
4 years ago
4(2x-5)+6=-3(-4x+8)-7
sladkih [1.3K]

Answer:

x = 4.25

Step-by-step explanation:

The given equation of line is :

4(2x-5)+6=-3(-4x+8)-7

Solving LHS,

4(2x-5)+6 = 8x-20+6

= 8x-14

Solving RHS,

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= 12x-31

So,

8x-14 = 12x-31

Taking like terms together,

8x-12x = -31+14

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