All categories

3 years ago

Find the slope of a line perpendicular to the line whose equation is 3y + 2x = 6

1 answer:

4 0

$3y + 2x = 6\\ \\the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\3y=-2x+6 \ \ /:3\\ \\y=-\frac{2}{3}x+\frac{6}{3}\\ \\y=-\frac{2}{3}x +2 \\ \\ m = -\frac{2}{3} \\ \\ Answer : \ slope \ is \ m = -\frac{2}{3}$

You might be interested in

Identify the ventez of the graph. Tell whether it is a minimum or maximum.

kotegsom [21]

Answer:

2nd option: the lowest point on the graph is (-2, -2). this is where both sides of the parabola converge. from this point, both lines go up. this means the vertex is a minimum.

3 0

2 years ago

Ok so if i want to build a city using 40 x 40 grid but i only wanna use 3/4 of the grid with titan fencing (300 dollars a square

astraxan [27]

160 plus 300 equal 460

5 0

3 years ago

Help middle school question!!!

Sav [38]

Answer:

<em>The shaded region has an area of 1400 square units</em>

Step-by-step explanation:

<u>Area of Compound Shapes</u>

We are given a shape and it's required to calculate its area. The shape can be divided into three rectangles as shown in the figure attached below.

The lengths of these rectangles are x, y, and z.

The value of x can be calculated as:

x = 60 - 15 - 10 = 35

Similarly:

y = 60 - 15 = 45

z = y = 45

The first rectangle has dimensions of x by 10, thus its area is:

A1 = 35*10 = 350

The second rectangle has dimensions of 60 by 10:

A2 = 60*10 = 600

The third rectangle has dimensions y by 10:

A3 = 55*10 = 450

The shaded area is:

A = 350 + 600 + 450 = 1400

The shaded region has an area of 1400 square units

8 0

2 years ago

Read 2 more answers

PLEASE HELP IM CRYING RN PLEASE ANSWER CORRECTLY AND YOU WILL GET BRAINLIEST AND 100 POINTS

Vlad [161]

Answer: B (x,y) --> (x + 4, y - 2)

Step-by-step explanation: When you add -5+4=-1, and when you subtract 2 from 4 it equals to 2, which gives you the second coordinates, this means that x+4 and y-2 is the answer.

8 0

3 years ago

2.1 & 2.2 Assessment: Vertex & Standard Form of Quadratic Functions

Brums [2.3K]

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill$

6 0

1 year ago