The answer should be D.
Hope it helped you.
30xy + 36x^2 + 30x + 25y
= 6x(5y + 6x) + 5(6x + 5y)
= (6x + 5)(6x + 5y) Answer
Answer:
Option A
Step-by-step explanation:
Domain should be greater than/equal to 1 for the function to be one-one.
f has vertex at (1,0)
f inverse has (0,1)
f(x) = 4
(x - 1)⁴ = 4
x = 2.414
On f: (2.414, 4)
On f inverse: (4, 2.414)
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>
<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>
<span>x = -2, 0, +2 so your answer is going to be e
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