The answer is going to be letter B
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.
Step-by-step explanation:
First, ask yourself: What is a polynomial? It's an algebraic expression in which all powers of x are zero or positive integers.
Eliminate E because -2 is not a positive integer exponent.
Accept D because all of the powers of x are positive integers: {3, 2, 1, 0}
Eliminate C because -3 is not a positive integer power
Eliminate A and B because of the fractional or negative exponents shown.
Only D is a polynomial.