All categories

3 years ago

What is 116.37 to the nearest foot.?

Mathematics

1 answer:

tatuchka [14]3 years ago

3 0

I'm assuming you're meaning 116.37 inches. 116.37 in = 9.6975 feet

Answer = 10 feet

You might be interested in

Assume the company surveys only people living in mountainous regions. If the company makes a generalization from this survey, ho

LenKa [72]

Answer:

The generalization will be biased because they are not surveying people from the other regions.

Step-by-step explanation:

3 0

2 years ago

Lia, Phil, and Cam collect a total of 200.30 dollars for a holiday fundraiser. Phil collects 12.80 dollars more than Lia. Cam co

kramer

Answer:

Lia collects $ 37.5 , Phil collects $50.3 and Cam collects dollars $ 112.5 .

Step-by-step explanation:

Let us assume that the dollar collect by the Lia be x .

As given

Lia, Phil, and Cam collect a total of 200.30 dollars for a holiday fundraiser.

Phil collects 12.80 dollars more than Lia.

Phil collects dollars = 12.80 + x

As given

Cam collects 3 times as much as Lia.

Cam collects dollars = 3x

Than the equation becomes

x + 12.80 + x + 3x = 200.30

12.80 + 5x = 200.30

5x = 200.30 - 12.80

5x = 187.5

$x = \frac{187.5}{5}$

x = $ 37.5

Thus

Lia collects dollars = $ 37.5

Phil collects dollars = 12.80 + 37.5

= $50.3

Cam collects dollars = 3 × 37.5

= $ 112.5

Therefore the Lia collects $ 37.5 , Phil collects $50.3 and Cam collects dollars $ 112.5 .

5 0

3 years ago

I need help with my rsm hwrk pls help me

oksian1 [2.3K]

Answer: $A= 32(\pi-2)\ cm^2, \ \ \ P=8\pi\ cm$

Step-by-step explanation:

When we consider Area under arc AC is is representing a quarter as ADBC is a square, $\angle D=90^{\circ}$ .

Area of quadrant = $\dfrac{\pi r^2}{4}$

here r= 8 cm

Area under Arc AC= $\dfrac{\pi (8)^2}{4}=16\pi\ cm^2$

Area of white region ABC = Area of square ADBC - Area under Arc AC

$=8^2-16\pi\ \ [\text{Area of square} = sides^2]\\\\= 64-16\pi\ \ =16(4-\pi)\ cm^2$

Similarly , Area of white region ADC = $16(4-\pi)\ cm^2$

Area of shaded region = Area of square - Area of white region ABC - Area of white region ADC

$=64-(64-16\pi)-(64-16\pi)\\\\= 32\pi-64\ cm^2 \\\\= 32(\pi-2)\ cm^2$

Area of shaded region = $= 32(\pi-2)\ cm^2$

Length of arc AC = $\dfrac{Circumference}{4}=\dfrac{2\pi r}{4}$

$\dfrac{\pi (8)}{2}=4\pi cm$

Perimeter of shaded region = 2(AC) = $8\pi\ cm$

3 0

3 years ago

HELP FAST PLEASE!!!!! Which of the following is an equation of the translation y = sin x, shifted π units up?

lianna [129]

to translate a graph up you need to add the amount you want to move it to the end of the equation, not to the variable.

The answer would be y = sin x + π

7 0

3 years ago

Misha deposited $3,725 into a savings account 22 years ago. The account has an interest rate of 2.2% and the balance is currentl

Annette [7]

The compounding equation is $A=P(1+ \frac{r}{n}) ^{nt}$ . So

$6012.37 = 3725(1+ \frac{0.022}{n}) ^{22n}$     Divide by 3725

$1.6141= (1+ \frac{0.022}{n}) ^{22n}$

Daily    = $(1+ \frac{0.022}{365}) ^{22*365}$
              = $(1.000060274) ^{8030}$
              = 1.6225
Monthly = $(1+ \frac{0.022}{12}) ^{22*12}$
              = $(1.0018333) ^{264}$
              = 1.6218
Quarter = $(1+ \frac{0.022}{4}) ^{22*4}$
              = $(1.0055) ^{88}$
              = 1.6204
Yearly = $(1+ \frac{0.022}{1}) ^{22*1}$
              = $(1.022) ^{22}$
              = 1.6141

The answer is yearly.

5 0

3 years ago