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Sophie [7]
3 years ago
7

Please help it’s polynomials

Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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At 50 years old, Margie gets her first job that requires 3% pre-tax income deposits to Social Security. Margie makes $35,000 a y
Vitek1552 [10]

Answer:

$14,847.46

Step-by-step explanation:

4 0
3 years ago
Find the value of x in each case: (See picture)
sergiy2304 [10]

Step-by-step explanation:

180-124=56°

180-56-2x-(180-6x)=0

180-56-2x-180+6x=0

-56+4x=0

4x=56

x=14°

........

2x=28

6x=84

5 0
3 years ago
How much fencing do i need for a garden that is 4 2/3 yards x 6 3/4 yards?
boyakko [2]
To find this, you have to turn them into inproper fractions. You do this by doing denominator x whole number x numerator. The equation is now 14/3 x 27/4. You have to do numerator x numerator and denominator x denominator which will lead us to an answer of 378/12 or 31 6/12 or 31 1/2

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3 years ago
What is this in scientific notation?!!!!
BlackZzzverrR [31]
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3 0
3 years ago
Suppose r(t) = (et cos t)i + (et sin t)j. Show that the angle between r and a never changes. What is the angle?
tatyana61 [14]

Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

As we know that,

velocity vector = v = \frac{dr}{dt}

Implies that

velocity vector = (e^{t} cost - e^{t} sint)i + (e^{t} sint - e^{t}cost )j

As acceleration is velocity over time so:

acceleration vector = a = \frac{dv}{dt}

Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

r.a = 0

Now, for angle between position vector r and acceleration vector a is given by:

cosФ = \frac{r.a}{|r|.|a|} = \frac{0}{|r|.|a|} = 0

Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

4 0
3 years ago
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