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Brut [27]
3 years ago
15

Plzz help me fast thanks

Mathematics
1 answer:
mixer [17]3 years ago
6 0

18/6 = 3

So the temperature dropped 3 degrees each day.

Hope this Helps!!

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Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16
HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image  PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

|A'B'|=k\times |AB|   .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}

PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}

It is noticed that the size of side in preimage is 2\sqrt{13} and the size of same side in image is \sqrt{13}.

Using equation (1), we get

\sqrt{13}=k \times 2\sqrt{13}

k=\frac{1}{2}

k=0.5

Hence, the value of scale factor is 0.5.

7 0
3 years ago
Read 2 more answers
A cold tablet contains the following amounts of active ingredients: acetaminophen 325 mg, chlorpheniramine maleate 2 mg, and dex
kakasveta [241]

Answer:

The number of tablets that can be prepared is 3076.

Step-by-step explanation:

The total amount of active ingredients in the tablet is the sum of the amounts provided in the formula:

325 mg + 2mg+15 mg=342 mg

The percentages of each component in the formula are:

Acetaminophen:\frac{325mg*100}{342mg}=95.03%

Chlorpheniramine maleate:\frac{2mg*100}{342mg} =0.58%

Dextromethorphan hydrobromide:\frac{15mg*100}{342mg}=4.39%

If 1 Kg=10^{6} mg of acetaminophen is used, the needed amount of chlorpheniramine maleate would be:

\frac{10^{6} mg *0.58}{95.03}=6153.85 mg

Since there are 125 g = 125000 mg of chlorpheniramine maleate, there is enough of these ingredient to run the available acetaminophen out. Thus, the total amount of active ingredients that can be prepared with 1 kg of acetaminophen is:

\frac{10^{6}mg*100}{95.03}=1052307.7mg

Since each tablet weighs 342 mg, the number of tablets that can be prepared is:

\frac{1052307.7mg}{342mg}=3076.923

Which means that 3076 tablets can be prepared and a there will be a remanent of 0.923*342 mg = 315.69 mg of active ingredients.

7 0
3 years ago
Rewrite the following equation in standard form.<br> y + 7 = 2(x - 6)
babunello [35]

Answer:

(-5)

Step-by-step explanation:

(-5)+7=2(×-6) fahhshzhsuhshzhhsbwysvavaghahahahwhwgwvavvwhhwshahwh

4 0
3 years ago
Question 5: perform without writing vertically<br>a) 50 x 513 x 2<br>how we can solve it​
Fynjy0 [20]
50x513 is 25,650, 25,650x2 is 51,300
5 0
3 years ago
X
Tom [10]

Answer:

but I have a great day of school and the other day

Step-by-step explanation:

  1. <em><u>H</u></em><em><u> </u></em><em><u>Tu</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>school</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>other</u></em><em><u> </u></em><em><u>day</u></em>
8 0
2 years ago
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