Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
X=4, first you distribute the 2 to both 4x and -11 which leaves you with 8x-22+9=19 next you add -22 with 9 which leaves you -13 the eqation now at 8x-13=19 so now you add 13 to both sides now youre left with 8x=32. Now the last step is to divide 8 on both sides. so that gives you the answer or X=4
I’m not sure if this is right but f(x) = 1/x + 3/2 ?
Answer:
Step-by-step explanation:
<u>Sum of interior angles of any triangle is 180°:</u>
- 52° + 43° + x = 180°
- 95° + x = 180°
- x = 180° - 95°
- x = 85°
