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miss Akunina [59]
2 years ago
7

good job on increasing our team sales from 90 to 130 units per day.” wow i never thought that we could increase our sales by

Mathematics
1 answer:
artcher [175]2 years ago
7 0

The sales was increased by 44.4%.

Step-by-step explanation:

  • Lets do this cumulative
  • 90 of 10 % =  9  which is 99
  • 90 of 10 % = 9 which is 108
  • 90 of 10% = 9 which is 117
  • 90 of 10% = 9 which is 126
  • 90 of 4 % = 3.6 which is 129.6
  • 90 of 0.044% = 0.0396 which is 129.99
  • This comes to nearly 44.44 to be closer there was an increase.
  • Always rule 1 approximation use 50% of 90 if it is above 130.
  • Down it to 40% of 90 see if the sales is lower than 130.
  • It should always start with 50,40,30....10 percents.
  • Alternative should be 10,1 or decimals.
  • Approximation using decimals rounding up becomes simple.

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Complete question :

A company is manufacturing highway emergency ares. Such ares are sup- posed to burn for an average of 20 minutes. Every hour a sample of ares is collected, and their average burn time is determined. If the manufacturing process is working cor- rectly, there is a 68% chance that the average burn time of the sample will be between 14 minutes and 26 minutes. The quality engineer in charge of the process believes that if 4 of 5 samples fall outside these bounds then this is a signal that the process might not be performing as expected. Each morning the sampling begins anew. Let X denote the number of samples drawn in order to obtain the fourth sample whose average value is outside of the above bounds. Find the probability that for a given morning X = 5, hence there seems to be a problem right away.

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Step-by-step explanation:

We are to find the probability for a given morning that X = 5

From the question, we could see that there is a 68% chance that the average burn time of the sample will be between 14 minutes and 26 minutes and the success of the process is obtained after the fourth or fifth sample.

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f(x) = \left[\begin{array}{ccc}x-1\\r-1\end{array}\right] (1-p)^x^-^r) (p)^r

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r = 4

p = 0.32

Substituting figures in the equation, we have:

P(x=5) = \left[\begin{array}{ccc}5-1\\4-1\end{array}\right] (1-0.32)^5^-^4 (0.32)^4

P(x=5) = \left[\begin{array}{ccc}4\\3\end{array}\right] (0.68)(0.01048576)

= 0.0285

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