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icang [17]
3 years ago
7

Help me with 1,2,3 pls thx

Mathematics
1 answer:
Softa [21]3 years ago
3 0
1. 4 meters per second 
2. D
3. the error is between lines 3 and 4 
You might be interested in
Point K is on line segment JL. Given KL = 2x – 2, JL = 4x + 9, and
sergeinik [125]

Answer:

JL = 21

Step-by-step explanation:

Given that K is on line segment JL, therefore:

KL + JK = JL (according to segment addition postulate)

KL = 2x - 2

JK = 5x + 2

JL = 4x + 9

Thus:

(2x - 2) + (5x + 2) = (4x + 9)

Solve for x

2x - 2 + 5x + 2 = 4x + 9

2x +5x - 2 + 2 = 4x + 9

7x = 4x + 9

Subtract 4x from both sides

7x - 4x = 4x + 9 - 4x

3x = 9

Divide both sides by 3

\frac{3x}{3} = \frac{9}{3}

x = 3

Find the numerical length of JL

JL = 4x + 9

Plug in the value of x

JL = 4(3) + 9 = 12 + 9 = 21

7 0
3 years ago
What is 100.2 percent as a fraction and decimal
notka56 [123]

Answer:

1.002 Decimal and 1 2/100 fraction

Step-by-step explanation:

Move the decimal 2 places to the right and make 100.2 1.002

think 100.2 over 100. we get 100 2/100 also know as 1whole and 2/100

7 0
3 years ago
Read 2 more answers
Please help me ASAP <br><br><br><br> What is 7/16 x 1/2
Alja [10]

Answer: 7/32

Step-by-step explanation:

Multiply straight across the numerator and do the same for the denominator.

7x1=7 (numerator)

16x2=32 (denominator)

Answer is 7/32

5 0
3 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
4 years ago
I promise its easy ok
Soloha48 [4]

Answer:

1)1/3

2)3

Step-by-step explanation:

rise over run then reduce

6 0
3 years ago
Read 2 more answers
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