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tatuchka [14]
3 years ago
9

Simplify 8 over the quantity of 2 plus 2i.

Mathematics
1 answer:
dexar [7]3 years ago
5 0

\dfrac{8}{2+2i}=\dfrac{8}{2(1+i)}=\dfrac{4}{1+i}=\dfrac{4}{1+i}\cdot\dfrac{1-i}{1-i}=\dfrac{4(1+i)}{1^2-i^2}\\\\=\dfrac{4(1+i)}{1-(-1)}=\dfrac{4(1+i)}{1+1}=\dfrac{4(1+i)}{2}=2(1+i)=2+2i\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\i=\sqrt{-1}\to i^2=-1

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If d is the common difference between terms in the sequence \{a_n\}, then

a_1=-21
a_2=a_1+d=-21+d
a_3=a_2+d=-21+2d
...
a_n=a_{n-1}+d=\cdots=-21+(n-1)d

You're told that S_{16}=-288 (the sum of the first 16 terms in the sequence, presumably). Well, we know that

S_{16}=\displaystyle\sum_{n=1}^{16}a_n=\sum_{n=1}^{16}(-21+(n-1)d)
S_{16}=\displaystyle(-21-d)\sum_{n=1}^{16}1+d\sum_{n=1}^{16}n

Recall that

\displaystyle\sum_{n=1}^kn=\frac{k(k+1)}2

so that we have

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So we get

\begin{cases}a_1=-21\\\\a_n=-21+\dfrac25(n-1)\end{cases}
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given:

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Now Given, by September her balance is 5 time as much as her June

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framing in equation form we get;

Balance in account till September = 5\times \$76.23 = \$381.15

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Now We need to find balance till December.

Kimmy balance till December will equal to sum of Balance in account in June and Balance in account till September and Balance Deposited in account between September and December.

framing in equation form we get;

Kimmy balance till December = \$76.23+ \$381.15+\$87.83 = \$545.21

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3 0
3 years ago
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mariarad [96]

Answer:

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