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SpyIntel [72]
4 years ago
15

The dimensions of this rectangle of half by seven show how you can divide the rectangle below to calculate the area

Mathematics
1 answer:
mariarad [96]4 years ago
8 0
Is that the whole thing?
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1.<br> 3z^2+ 8z-3<br> in quadratic formula
tensa zangetsu [6.8K]

Answer:

What grade of math is this?

Step-by-step explanation:

4 0
3 years ago
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
Sergeu [11.5K]
Hello!

First of all we find the slope by dividing the difference of the y values by the difference of the x values as seen below.

\frac{-3-11}{1+3} = -\frac{14}{4} = \frac{7}{2}

The slope of our line is 7/2, or 3.5
-------------------------------------------------------------
Now we will put the slope and a point on our line into slope intercept form and solve for b. We will use (-3,11).

11=3.5(-3)+b
11=10.5+b
b=0.5

Our final equation is shown below.

y=3.5x+0.5

I hope this helps!


7 0
3 years ago
Read 2 more answers
Write the percent as a mixed number in simplest form.<br> 168%
vladimir2022 [97]

Answer:

1 and 17/25

Step-by-step explanation:

First, you make it into a fraction. So because percents are out of 100, it would be 168/100. Then, you take 100 out of it to get a mixed number, 1 and 68/100, and then simplify 68/100 by dividing both sides by the greatest common factor, which is 4. 68/100÷4=17/25. The answer would be 1 and 17/25.

(hope this helps :P)

4 0
3 years ago
The graph of the equation xy=4 is symmetric with respect to which of the following?
inna [77]
The graph of x and y = 4 is symmetric with respect to the line x = y.
 Therefore, the answer is the second option shown above, which is:

 <span>the line y = x</span>
 
 Below is a graph where you can see the symmetry of xy = 4 with respect to the oblique axis x = y. This axis cuts the curves just at its apex

4 0
3 years ago
Which of the following functions are solutions of the differential equation y" + y = 7 sin(x)? (Select all that apply.)
Nikitich [7]

The homogeneous equation

y'' + y = 0

has characteristic equation

r² + 1 = 0

with roots at r = ± √(-1) = ± i, and so the characteristic solution is

y = C₁ cos(x) + C₂ sin(x)

Using the method of undetermined coefficients, suppose

y = a x cos(x) + b x sin(x)

(we would normally consider y = a cos(x) + b sin(x), but cos(x) and sin(x) are already part of the characteristic solution)

The derivatives are

y' = a cos(x) - a x sin(x) + b sin(x) + b x cos(x)

y' = (b - a x) sin(x) + (a + b x) cos(x)

and

y'' = -a sin(x) + (b - a x) cos(x) + b cos(x) - (a + b x) sin(x)

y'' = (-2a - b x) sin(x) + (2b - a x) cos(x)

Then

y'' + y = (-2a - b x) sin(x) + (2b - a x) cos(x) + a x cos(x) + b x sin(x)

7 sin(x) = -2a sin(x) + 2b cos(x)

and it follows that a = -7/2 and b = 0.

So, the general solution to the DE is

y = C₁ cos(x) + C₂ sin(x) - 7/2 x cos(x)

which means the only valid solutions from the given choices are

y = 7 sin(x)

y = 7 cos(x)

4 0
2 years ago
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