All categories

2 years ago

Least common multiple of 6 and 42

Mathematics

2 answers:

Murrr4er [49]2 years ago

5 0

The least common multiple of 6 and 42 is 42 I believe

4vir4ik [10]2 years ago

4 0

7 is the leases common I’m pretty sure

You might be interested in

Solve this please math problem asap please

Gennadij [26K]

Answer:

Step-by-step explanation:

Hope this helps

4 0

2 years ago

Read 2 more answers

Answer the questions from the picture Step by step

andre [41]

Answer:

6 = 4 mins

Step-by-step explanation:

you have to take 200 and 50 and divide them

200 divided by 50 =4 and you have to tack mins to the end of it

id_k how many class rooms for number 5

and 7 i dk how many weeks there are therefore i cant solve them

7 0

1 year ago

Which of the following rational functions is graphed below?

vampirchik [111]

Answer:

The correct option is D.

i.e.

$f\left(x\right)=\frac{1}{x\left(x+4\right)}$ is the correct option.

The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

$f\left(x\right)=\frac{1}{x\left(x+4\right)}$

$\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x$

$\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{None}$

$\mathrm{Extreme\:Points\:of}\:\frac{1}{x\left(x+4\right)}:\quad \mathrm{Maximum}\left(-2,\:-\frac{1}{4}\right)$

So, the correct graph is shown in attached figure.

Therefore, the correct option is D.

i.e.

$f\left(x\right)=\frac{1}{x\left(x+4\right)}$ is the correct option.

7 0

3 years ago

At a certain fast-food restaurant, 69 % of customers order a chicken sandwich, 46 % of customers order french fries, and 36 % of

Leviafan [203]

We have events:

A - customer orders a chicken sandwich
B - customer orders french fries

and probabilities:

$P(A)=0.69\\\\P(B)=0.46\\\\P(A\cap B)=0.36$

so:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.69+0.46-0.36=\boxed{0.79}$

7 0

2 years ago

Please help, will give brainliest! :)

Nonamiya [84]

Answer:

the answer is 2>am sorry if wrong

6 0

1 year ago