vertical assymtotes are in the form x=something, not y=0 y=0 are horizontal assemtotes
so verticall assymtotes reduce the fraction set the denomenator equal to zero those values that make the deomenator zero are the vertical assymtotes
the horizontal assymtote when the degree of P(x)<q(x), then HA=0
when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x) example, f(x)=(2x^2-3x+3)/(9x^2-93x+993), then HA is 2/9
ok so for vertical assymtote example f(x)=x/(x^2+5x+6) the VA's are at x=-3 and x=-2
horizontal assymtote make degree same f(x)=(3x^2-4)/(8x^2+9x), the HA is 3/8 hope I helped, read the whole thing then ask eusiton
