Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that
. Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that
. In this equality we can perform a right multiplication by
and obtain
. Then, in the obtained equality we perform a left multiplication by P and get
. If we write
and
we have
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have
and from B↔C we have
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and
. So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.
Answer:
(2x + 3)(x - 2)
Step-by-step explanation:
use FOIL
First, Outside, Inside, Last
2x x x = 2x²
2x x -2 = -4x
3 x x = 3x
3 x -2 = -6
2x² - 4x + 3x - 6
The answer is c. 240π
V=πr² h/3 =π×6²× 20/3 ≈753.98224
Answer:
-312
Step-by-step explanation:
Volume of a cone = PI x r^2 x h/3
Volume = PI x 5^2 x 9/3
Volume = 235.62 cubic cm.
Volume of a block of wax = L x W x H
Volume = 2 x 4 x 3 = 24 cubic cm.
Total number of blocks = Volume of cone / volume of blocks:
235.62 / 24 = 9.82
Round up to 10.
They will need 10 blocks.