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2 years ago

Forty students are in the drama club. If 3/8 of the club members have roles in the spring play how many students give the part

Mathematics

1 answer:

Sati [7]2 years ago

7 0

15 students have roles and 25 do not I hope this is right or at least helps :)

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What is the inverse of cube root x/3 +1

Ostrovityanka [42]

Answer:

${f}^{ - 1} (x) = 3 {x}^{2} - 3$

Step-by-step explanation:

We want to find the inverse of

$y = \sqrt[3]{ \frac{x}{3} + 1}$

We interchange x and y to get:

$x= \sqrt[3]{ \frac{y}{3} + 1}$

We solve for y;

${x}^{2} = \frac{y}{3} + 1$

Multiply through by 3

$3 {x}^{2} = y + 3$

Subtract 1 from both sides:

$y = 3 {x}^{2} - 3$

Therefore the inverse is

${f}^{ - 1} (x) = 3 {x}^{2} - 3$

8 0

2 years ago

Forty six times y is no more than 276

Step2247 [10]

Answer:

y ≤ 6

Step-by-step explanation:

<u>Step 1: Convert words into an expression</u>

Forty six times y is no more than 276

46 * y ≤ 276

<u>Step 2: Solve for y</u>

46 * y / 46 ≤ 276 / 46

y ≤ 6

Answer: y ≤ 6

4 0

2 years ago

Read 2 more answers

Rafael counted a total of 40 white cars and yellow cars there were nine times as many white cause as yellow cars how many white

gregori [183]

(White cars)9+1(yellow cars

40 divided by 10 is 4

4 is the amount of yellow cars so take that away from 40

Your answer is 36

8 0

2 years ago

Rule add 7 first term 3

Grace [21]

3 10 17 24 31 38 because 3 plus 7 equals 10

4 0

2 years ago

You are going to paint a six-sector spinner. There are 4 colors to choose from. How many different ways can you paint the spinne

emmainna [20.7K]

Using the Fundamental Counting Theorem, it is found that there are 648 ways to paint the spinner.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

In this problem, we have that the first sector can be painted in any of the 4 colors, the others until the 5th can be painted in 3 colors(not the adjacent), and the sixth in only 2, as it is adjacent to both the 5th and the 1st sectors, hence:

$n_1 = 4, n_2 = n_3 = n_4 = n_5 = 3, n_6 = 2$

Hence the number of ways is given by:

N = 4 x 3 x 3 x 3 x 3 x 2 = 648.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

4 0

1 year ago