Ask question

Ask question

All categories

3 years ago

6

Forty students are in the drama club. If 3/8 of the club members have roles in the spring play how many students give the part

1 answer:

Sati [7]3 years ago

7 0

15 students have roles and 25 do not I hope this is right or at least helps :)

You might be interested in

4) Jerry cuts a piece of paper from one corner to the other, as shown. How long is the cut edge (look at photo)

kirill115 [55]

Answer:

i think its 10 or 20

Step-by-step explanation:

7 0

3 years ago

Hey need help real quick!<br> factor x^2 - 4x^3

dezoksy [38]

Answer: x^2(1-4x)
Explanation: factor x^2 out of x^2 - 4x^3

4 0

2 years ago

Re-write the equation after you distribute<br> and combine all the like terms.<br> 12-4(-3x+5)-8x=20

dlinn [17]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

3 0

3 years ago

Jane is planting a mixture of flowers. For every ounce of Marigold seeds she uses 2/5 of an ounce of lupine seeds how many ounce

dusya [7]

Answer:

$\frac{5}{2}$ ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.

We will use proportions to solve our given problem.

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}$

Let us simplify our proportion as shown below:

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}$

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}$

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

$\frac{\text{Marigold seeds}}{1}=\frac{5}{2}$

$\text{Marigold seeds}}=\frac{5}{2}$

Therefore, Jane will use $\frac{5}{2}$ ounces of marigold seeds, if she used one ounce of lupine seeds.

6 0

3 years ago

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago