Answer:
Not a function.
Does not pass vertical line test.
B.
Step-by-step explanation:
Something called a vertical line test is used to determine if a relation that has been graphed is a function or not.
We say if it passes then it is a function.
It will pass if you are able to draw infinitely many vertical lines covering the whole graph and each vertical line either touches your relation once or none.
If a single vertical line that you draw touches more than once, then it isn't a function.
When I say draw, I don't mean you should physically do it, but more so imagine it.
Now this particular relation is not a function because I can find a vertical line that touches more than once. Take the vertical line x=5 for example.
It will touch at (5,-6) and (5,6). You cannot have an x assigned to more than one y.
Answer:
0.07
Step-by-step explanation:
to find the IQR you do Q3-Q1
2.00-1.93
I'm assuming that the diagonals intersect at E. Since diagonals of a parallelogram bisect each other, BE=ED.
- 7x-2=x²-10
- x²-7x-8=0
- (x-8)(x+1)=0
- x = -1, 8
As distance must be positive, we reject the negative case, so x=8.
Thus, BE=ED=54.
The solution to the quadratic equation are option C) x= -5 and option E) x=3.
<u>Step-by-step explanation</u>:
The given quadratic equation is x²+2x-15 = 0.
Using the factorization method,
- product of the roots should be -15.
- Sum of the roots should be 2.
⇒ -15 = 5 
-3
⇒ 2 = 5+(-3)
(x+5)(x-3) = 0
Therefore, x = -5 and x = 3
