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slamgirl [31]
2 years ago
7

What is π⋅π⋅π⋅x⋅x⋅x⋅x+ ?

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
6 0

Answer:

4xπ^3

Step-by-step explanation:

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Indicate in standard form the equation of the line passing through the given points.
Lynna [10]
(-2,2)(5,1)

slope(m) = (1 - 2) / (5 - (-2) = -1 / 7

y = mx + b
slope(m) = -1/7
use either of ur points....(5,1)....x = 5 and y = 1
now sub and find b, the y int
1 = -1/7(5) + b
1 = -5/7 + b
1 + 5/7 = b
7/7 + 5/7 = b
12/7 = b

equation is : y = -1/7x + 12/7....but we need it in standard form...

y = -1/7x + 12/7
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The average hourly earnings for a construction worker is projected to be $24.50 in 2012. jason wants to join the construction wo
Talja [164]

The statement his friend’s statement  is not accurate. The percent increase will be more than 2% is correct.

We have the average hourly earnings for a construction worker is projected to be $24.50 in 2012. jason wants to join the construction work force after he graduates in 2012. his friend tells him that average hourly earnings for construction workers will rise by 2% from 2009 to 2012.

<h3>What is the meaning of avarage?</h3>

An average value is defined as the sum of all the values divided by the total number of values in a given data.

Therefore we get,have ion industry  average hourly earnings, 2000-2009 a line graph titled construction industry, average hourly earnings (dollars), 2000 to 2009,

where the x-axis shows years and the y-axis shows average hourly earnings of production workers.

line starts at 17.2 on january 2000, slowly increases to 19.7 on january 2006, then increases more quickly to 20.5 on january 2007 and 22.4 on january 2009

<h3>What is the meaning of increasing 2%?</h3>

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

Therefore from the given data line starts

17.2 on january 2006

20.5 on janury 2007

22.4 on janury 2009

It seems that The option B is correct.

Therefore,his friend’s statement  is not accurate. The percent increase will be more than 2%.

To learn more about the percentage value visit:

brainly.com/question/11360390

7 0
2 years ago
Ixl/Signin/Eli whitney Help please
Dafna1 [17]
What do you mean about his
3 0
3 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
1 year ago
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