Answer:
The group will end up with 12 1/2 of yarn in total.
Step-by-step explanation:
L= W+5
P= 9W
P= 2L+ 2W
9W= 2(W+5) + 2W
9W= 2W +10 +2W
9W = 4W +10
5W = 10
W = 2
L=7
P= 9(2)
P= 18
A= LW
A= 7 x 2
A= 14
To find the inverse of any function, switch the x's with y's and vice versa.
The current equation given is ![y=4x-8](https://tex.z-dn.net/?f=%20y%3D4x-8%20)
Switch the
with
and switch the
with ![y](https://tex.z-dn.net/?f=y)
After doing so, we'll have the following equation:
![x=4y-8](https://tex.z-dn.net/?f=%20x%3D4y-8%20)
Now, let's move the variables around so that y is isolated on the left side again.
Subtract both sides by 4y
![x-4y=-8](https://tex.z-dn.net/?f=%20x-4y%3D-8%20)
Subtract both sides by x
![-4y=-8-x](https://tex.z-dn.net/?f=%20-4y%3D-8-x%20)
Divide both sides by -4
![y= \dfrac{x}{4}+2](https://tex.z-dn.net/?f=%20y%3D%20%5Cdfrac%7Bx%7D%7B4%7D%2B2%20)
That is the answer.
Have an awesome day!
(ノ◕ヮ◕)ノ*:・゚✧
F because a square is also part of a diamond a kite is not a square.
Answer:
B. This statement is false. A true statement is, "As the size of a sample increases, the standard deviation of the distribution of sample means decreases
Step-by-step explanation:
Standard deviation of distribution of sample means = ![\sigma_{m}](https://tex.z-dn.net/?f=%5Csigma_%7Bm%7D)
Sample size = n
Population standard deviation = ![\sigma](https://tex.z-dn.net/?f=%5Csigma)
The formula to calculate the standard deviation of distribution of sample means is:
![\sigma_{m}=\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Csigma_%7Bm%7D%3D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
From the above relation we can see that:
Standard deviation of the distribution of sample means is inversely related to the sample size. In inverse relation if one quantity increases the other will decrease. So, if the size of the sample is increased, the standard deviation of the distribution of sample means will Decrease.
Hence, the given statement is False. Therefore, the correct answer will be:
B. This statement is false. A true statement is, "As the size of a sample increases, the standard deviation of the distribution of sample means decreases"