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BigorU [14]
3 years ago
15

Need help...

Mathematics
2 answers:
Delvig [45]3 years ago
5 0
2 / (1/4) =
2 * 4 =
8 total students
11111nata11111 [884]3 years ago
4 0
Carol gave a piece of paper to 8 students.

8 times 1/4 = 2 sheets of paper that Carol originally had.


You might be interested in
11z/16+7z/8=5/16 as a decimal
babunello [35]
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
4 0
3 years ago
What is the equation of the line passing through the points (4, -7.5) and (6, -3.5) in slope-intercept form?
Ratling [72]

Answer:

Your answer will be

y=2x-15.5

Step-by-step explanation:

Hi, there you must know the slope-intercept form which is

y=mx+b

m=slope

b=y-intercept

You can also use

the slope formula which is

\frac{y_2-y_1}{x_2-x_1}

in this case

it will look like this

\frac{-7.5-(-3.5)}{6-4}=\frac{-4}{2}=-2

So the slope is -2

Now we will find the y-intercept

-7.5=2(4)+b

-7.5=8+b   Subtract 8 both sides

-15.5=b

Your y-intercept is -15.5

Hope this helps

6 0
3 years ago
analyze this situation and determine how much cookie dough is "wasted" when 3-inch cookies are cut. then have each team member c
Cerrena [4.2K]

Answer:

The result is the same.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

Given the information:

  • square 12 inches wide
  • 3-inch diameter cookies are cut => its radius is: 1.5 inches

Hence we can find some information:

  • The area of the square is: 12^{2}  = 144 square inches
  • The area of a cookies is: r^{2}π = 3.14*1.5^{2} = 7.065 square inches
  • The total number of 3-inch cookies are: 4*4 =16

=> The total area of the cookies is: 16* 7.065 = 113.04 square inches

=> how much cookie dough is "wasted" when 3-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

If the diameter is increased to 4 inches => its radius: 2 inches, we have:

  • The area of a cookies is: r^{2}π = 2^{2} *3.14 = 12.56 square inches
  • The total number of 3-inch cookies are: 3*3 =9

=> The total area of the cookies is: 9* 12.56 = 113.04 square inches

=> how much cookie dough is "wasted" when 4-inch cookies are cut:

= The area of the square - The total area of the cookies

= 144 - 113.04 = 30.96  square inches

The result is the same.

8 0
3 years ago
11+m>15 what’s the answer for this problem?
hjlf

Answer:

m > 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

11 + m > 15

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Subtract 11 on both sides:                    m > 4

Here we see that any value <em>m</em> greater than 4 would work as a solution to the inequality.

6 0
3 years ago
WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

5 0
4 years ago
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