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Orlov [11]
3 years ago
12

B) (1 - cos B)(1 + cos B) = 1/cosec^2(B)

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

Proved

Step-by-step explanation:

(1-cosB)(1+cosB)=\frac{1}{cosec^2B} \\\\Use\\\\ (a+b)(a-b)=a^2-b^2 ,\\so,\\=(1)^2-(cosB)^2\\=1-cos^2B\\\\Now\ ,  we\ know\ \\sin^2B+cos^2B=1\\\\so,\\sin^2B=1-cos^2B\\so we just replace,\\\\=1-cos^2B=>sin^2B\\and\ since\ sinB=\frac{1}{cosecB} \\\\=sin^2B=>\frac{1}{cosec^2B}\\

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
Luiza is jumping on a trampoline.
lyudmila [28]

Answer:

The second time when Luiza reaches a height of 1.2 m = 2 08 s

Step-by-step explanation:

Complete Question

Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.

H(t) = -0.6 cos (2pi/2.5)t + 1.5.

What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.

Solution

Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as

H(t) = -0.6cos⁡(2π/2.5)t + 1.5

What is t when H = 1.2 m

1.2 = -0.6cos⁡(2π/2.5)t + 1.5

0.6cos⁡(2π/2.5)t = 1.2 - 1.5 = -0.3

Cos (2π/2.5)t = (0.3/0.6) = 0.5

Note that in radians,

Cos (π/3) = 0.5

This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,

Cos (5π/3) = 0.5

So,

Cos (2π/2.5)t = Cos (5π/3)

(2π/2.5)t = (5π/3)

(2/2.5) × t = (5/3)

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Hope this Helps!!!

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Step-by-step explanation:

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