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Orlov [11]
3 years ago
12

B) (1 - cos B)(1 + cos B) = 1/cosec^2(B)

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

Proved

Step-by-step explanation:

(1-cosB)(1+cosB)=\frac{1}{cosec^2B} \\\\Use\\\\ (a+b)(a-b)=a^2-b^2 ,\\so,\\=(1)^2-(cosB)^2\\=1-cos^2B\\\\Now\ ,  we\ know\ \\sin^2B+cos^2B=1\\\\so,\\sin^2B=1-cos^2B\\so we just replace,\\\\=1-cos^2B=>sin^2B\\and\ since\ sinB=\frac{1}{cosecB} \\\\=sin^2B=>\frac{1}{cosec^2B}\\

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7. The largest of the Great Pyramids in Egypt was built with a square base,
strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

                            = (754)²

                            = 568516 square feet

Volume of the pyramid = \frac{1}{3}(\text{Area of the base})(\text{Height})

                                       = \frac{1}{3}\times 568516\times 481

                                       = 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = \frac{1}{3}(555025)(471)

                                       = 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0
4 years ago
What properties will you use next to solve the equation
ella [17]

Answer:

To solve an equation you can use PEMDAS, standing for parenthesis, exponents, multiplication, division and addition. If it's an equation like, x/3+7+13, you could use the distributive property. By separating variables.

Step-by-step explanation:

7 0
3 years ago
Find the equation of the line through the point (2, 5) that cuts off the least area from the first quadrant. Give your answer us
Amanda [17]

The equation of the line would be

y = mx+b 

where m is the slope, b is the y intercept. 

<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept and the base is y intercept divided by slope. Therefore,</span>

A = b^2/2m

At point (2,5)

5 = 2m+b

Substitute that in the area

A = b^2/5-b to find the least area, differentiate the area with respect to the height and equate it to 0 

dA/db = 0

<span>find b and use that to find m. Then, you can have the equation of the line.</span>


4 0
3 years ago
Read 2 more answers
Please help me, ill give brainiest to correct answer
MAXImum [283]

Answer:

B.

Step-by-step explanation:

6 is left after crossing from end to end.

3 0
3 years ago
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The length of a garden is 125% of its width. If the width of the garden is 8 meters, what is the area of the garden
PtichkaEL [24]
L= 125/100* w=5/4* 8=10 m

the area =10*8=80 m^2
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3 years ago
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