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3 years ago

A kite was broken into two triangles.

2 answers:

5 0

<h2>Answer:</h2><h2>Area of the kite = 80 $cm^{2}$ , Area of traingle = 40 $cm^{2}$ and height of the triangle, h = 5 cm</h2>

Step-by-step explanation:

A kite is broken into two triangles

Given the base of the traingle, b = 16 cm

Height of the triangle, h = 5 cm

Area of traingle = $\frac{1}{2} (b.h)$

= $\frac{1}{2} (16) (5)$

= 40 $cm^{2}$

Area of the kite = area of triangle 1 + area of triangle 2

= 40 + 40

= 80 $cm^{2}$

Dafna11 [192]3 years ago

3 0

Answer:

Area of the kite = 80 , Area of traingle = 40 and height of the triangle, h = 5 cm

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2 years ago

Read 2 more answers

Solve the system by graphing. Write the solution as an ordered pair. y = 1/3x + 2 y = –x – 2

Dima020 [189]

ANSWER

The solution is where the two graphs intersect, which is
$(-3,1).$

EXPLANATION

The given system of equations are
$y = \frac{1}{3} x + 2$
and

$y = - x - 2$

We need to graph the two equations.

Let us graph

$y = \frac{1}{3} x + 2$
first.

We need at least two points.

You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.

When
$x = 0$

$\Rightarrow \: y = \frac{1}{3} (0) + 2$

$\Rightarrow y = 0 + 2$

$\Rightarrow y = 2$

So this gives us the ordered pair,

$(0,2)$

When
$y = 0$
we get,

$0= \frac{1}{3} x + 2$

$\Rightarrow \: - 2 = \frac{1}{3} x$

$\Rightarrow \: - 2 \times 3= x$

$\Rightarrow \: -6= x$
This also gives the ordered pair

$(-6,0).$

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.

For the second line

$y = - x - 2$

We again find the intercepts and plot them.

When
$x = 0$

$y = - 0 - 2$

$\Rightarrow \: y = - 2$

This gives the ordered pair

$(0,-2)$

Also, when
$y = 0$

then we have,

$0 = - x - 2$

$2 = - x$

$x = - 2$

Then we again have the ordered pair,

$(-2,0)$

We plot these two points on the same graph sheet to obtain the red graph above.

The intersection of the two lines is
$(-3,1)$

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2 years ago

The lines shown below are perpendicular. If the green line has a slop of 2/5, what is the slope of the red line?

aivan3 [116]

The slope of the red line that is perpendicular to the green line is: -5/2.

<h3>What are the Slope Values of Perpendicular Lines?</h3>

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

<h3>What is the Negative Reciprocal of a Number?</h3>

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

Learn more about slope of perpendicular lines on:

brainly.com/question/1362601

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