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3 years ago

14

Gabriela has taken 33 quizzes and her average score so far is 8080. if she gets 100100, a perfect score, on the remaining 22 qui

zzes, what will her new average be?

1 answer:

allochka39001 [22]3 years ago

7 0

Her average will be 100078

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Stear Corp. has an opening inventory of $2,500. During the year, it made purchases worth $55,000. at the end of the accounting p

Masja [62]

Answer:

B

Step-by-step explanation:

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3 years ago

Kayla bought a car that's price was reduced by 34%. The original price for the car was $16,000. How much did she spend on the ca

aliya0001 [1]

The price was reduced by 34%, so she paid 100-34 = 66% of the original price.

16,000 x 0.66 = 10,560

She paid $10,560

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3 years ago

Read 2 more answers

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

3 years ago

jamal is going to borrow 14000 from his credit union to buy a used car. the APR is 7.0% and the length of the loan is 4 years. h

ELEN [110]

The formula to use here would be:

A = P(1+r)^t where P is the principal (starting) amount, r is the rate of interest, and t is time. Knowing this, plug in your values:

A = 14,000(1+0.07)^4 once worked out, you should get $18,351.14414 < this is the total amount he would be paying at the end of 4 years. to find the interest, subtract this amount from the principal amount (14,000):

$18,5351.14414 - 14,000 = 4,351.14414 < this is the amount of interest. Round your answer.

Answer: Jamal will pain $4,351.14 interest.

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3 years ago

It cost Naomi $7.70 to send 154 text messages how many text messages did she send if she spent $5.25

igomit [66]

Answer:

105 text messages

Step-by-step explanation:

7.70 divied by 154 = 0.05

0.05 per text massage

5.25 divided by 0.05 = 105

to check work:

105 times 0.05 = 5.25

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3 years ago