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stiv31 [10]
3 years ago
13

Let f(x) = (6x^3 – 7)^3 and g(x) = 6x^3 - 7. Given that f(x) = (hog)(x), find h(x).

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Answer:

h(x) = x^3.

Step-by-step explanation:

h(x) = x^3

because (h o g)(x)  = (6x^3 - 7)^3.

alexgriva [62]3 years ago
4 0

Answer:

<h2>h(x) = x³</h2>

Step-by-step explanation:

\text{We can notice:}

g(x)=6x^3-7,\ f(x)=(\underbrace{6x^3-7}_{g(x)})^3=\bigg(g(x)\bigg)^3

\text{If}\ f(x)=(h\circ g)(x)=h\bigg(g(x)\bigg),\ \text{then}\ h(x)=x^3

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A=c+(-10) Solve for c in terms of other variables.
True [87]
To do this we need to move 10 to other side.  To accomplish this you just need to add 10 to both side since (-10) 

so 
A+ 10 = c -10 + 10 
we get
A+ 10 = c

lets say it wasn't -10 but positive 10. 

A = c + 10  then we would subtract 10 from both sides

A -10 = c + 10 - 10 
we get 
A  - 10 = C 
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3 years ago
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8 0
3 years ago
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ANTONII [103]

Answer:

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6 0
3 years ago
How do you write 250% as a fraction or mixed number in simplest form?
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8 0
3 years ago
When the price is $ 40 per radio, a producer will supply 90 radios each month for sale. For each $4 increase in price the produc
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Price for a radio = $ 40 for supply 90 radios in a month.

Ratio of increase in price to the number of radios supplies in a month 4:8 that is 1:2.

New unit price given  = $76.

Difference in unit price given in starting and New unit price = 76-40=$36

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5 0
3 years ago
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