All categories

3 years ago

Find an equation of the line perpendicular to the graph of 4x-2y=9 that passes through the point at (4,6)

Mathematics

2 answers:

Radda [10]3 years ago

7 0

d..........................

olga nikolaevna [1]3 years ago

5 0

Perpendicular means the slope is the opposite inverse
Lets re-organize the equation so its more friendly
4x-2y=9
-2y=-4x-9
y=2x+9/2
The slope of this is 2, so the opposite inverse would be -1/2
So far our new equation looks like y=-1/2x+b
To find B we will input the coordinates (4,6) for their respective x,y values
6=-1/2(4)+b
6=-2+b
b=8
y=-1/2x+8
The answer is B

You might be interested in

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

4/15:8 3/7:7/10 3.3/5:4.1/2

posledela

I don't understand what you are trying to ask if you post this in question form or add a question I can probably help you other than that I don't think anyone knows what you need help with, I'm sorry sweety

4 0

3 years ago

Find the exact value of sec 5pi/4.

Papessa [141]

Answer:

-(sqrt2)

Step-by-step explanation:

3 0

3 years ago

X/3 +11=1/15 solve the following equation

fenix001 [56]

here is what i get :
x/3+11-(1/15)=0

7 0

3 years ago

Read 2 more answers

Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)

laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2) (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0

4 years ago