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Archy [21]
2 years ago
7

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

Mathematics
1 answer:
Rama09 [41]2 years ago
5 0

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The vertex B is at (1, 5), then vertex B' is at (-2, 11).

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.

∆ABC is translated 6 units up and 3 units left to create ∆A'B'C'.

The vertex A is at (-1, 2), then vertex A' is at,

A' = (-1-3, 2+6) = (-4, 8)

The vertex B is at (1, 5), then vertex B' is at,

B' = (1-3, 5+6) = (-2, 11)

Learn more about Triangle:

brainly.com/question/2773823

#SPJ1

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the answer would be 35

Step-by-step explanation:

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vagabundo [1.1K]

\frac{50}{12} x 12

the 12 in the numerator (top) and the 12 in the denominator (bottom) cross out so you are left with 50.

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Solve AABC. Round your answers to the nearest hundredth, if necessary
Aloiza [94]

Answer:

C=25^{\circ},\\a\approx 10.72,\\b\approx 11.83

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees. Thus, angle C must be 180-90-65=25^{\circ}.

In any triangle, the Law of Sines is given by \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}.

Therefore, we have:

\frac{\sin 90^{\circ}}{b}=\frac{\sin 25^{\circ}}{5},\\\\b=\frac{5\sin90^{\circ}}{\sin 25^{\circ}}=11.8310079158\approx \boxed{11.83}

\frac{a}{\sin 65^{\circ}}=\frac{5}{\sin25^{\circ}},\\a=\frac{5\sin 65^{\circ}}{\sin25^{\circ}}=10.7225346025\approx \boxed{10.72}

8 0
3 years ago
I need to know how to do this last problem
butalik [34]
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4 0
3 years ago
The lowest point in Death Valley is Badwater at 282 feet below sea level. The highest point in
Finger [1]

Answer:

Step-by-step explanation:

Given

Badwater = -282ft

Telescope\ Peak = 11043ft

The position of badwater is negated because it is below sea level

The interpretation of the question, is to calculate the distance between the two given points.

This is calculated as:

Difference = Telescope\ Peak - Badwater

Difference = 11043ft - (-282ft)

Open bracket

Difference = 11043ft+282ft

Difference = 11325ft

<em>Hence, the distance between both is 11325ft</em>

8 0
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