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abruzzese [7]
3 years ago
5

A laptop computer has two internal signals: An unplugged signal, which is '1' if the laptop's power supply is connected, and '0'

otherwise. A low battery signal, which is '0' if the laptop's battery has reached an almost empty state, and '1' otherwise. Suppose the laptop's power control system accepts a single hibernate signal which determines if the laptop should change its current operating state and shut down. If the laptop should shut down when the battery is low and its charger is unplugged, which gate could be used to produce the hibernate signal?
Computers and Technology
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

The correct usage is a NOR gate which is indicated in the explanation.

Explanation:

The truth table for the given two signals, namely

p=unplugged signal

q=low battery signal

can  form a truth table of following form

Here p has 2 states

1 if the power supply is connected

0 otherwise

Similarly q has 2 states

0 if the battery has reached almost zero state

1 otherwise

As the condition for the Hibernate Signal is given as to only activate when the battery is low and the power supply is not connected. This indicate that the value of Hibernate signal should be 1 when both p and q are 0.

Using this condition, the truth table is formed as

unplugged signal | low battery signal |  Hibernate Signal

            0               |                 0             |             1

            0               |                 1              |             0

            1                |                 0             |             0

            1                |                 1              |             0

Now the truth table of NOR is given as

a    |     b    |  a or b   |   ~(a or b)

0    |     0    |      0      |        1

0    |     1     |      1       |        0

1     |     0    |      1       |        0

1     |     1     |      1       |        0

This indicates that the both truth tables are same thus the NOR gate is to be used for this purpose.

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64

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Write a program that declares an array named myArray with 8 components of the type int. Initialize the array to 8 values that th
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Answer:

#include <iostream>

using namespace std;

void filterEvens(int myArray[]) {

   for (int i = 0; i < 8; ++i) {

     if(myArray[i]%2==0){

         cout<<myArray[i]<<" ";

     }

  }

}

int main(){

   int myArray[8];

   for(int i =0;i<8;i++){

       cin>>myArray[i];

   }

   filterEvens(myArray);

   return 0;

}

Explanation:

The solution is provided in C++

#include <iostream>

using namespace std;

The function filerEvens is defined here

void filterEvens(int myArray[]) {

This iterates through the elements of the array

   for (int i = 0; i < 8; ++i) {

This checks if current element is an even number

     if(myArray[i]%2==0){

If yes, this prints the array element

         cout<<myArray[i]<<" ";

     }

  }

}

The main begins here

int main(){

This declares an integer array of 8 elements

   int myArray[8];

The following iteration allows input into the array

<em>    for(int i =0;i<8;i++){</em>

<em>        cin>>myArray[i];</em>

<em>    }</em>

This calls the defined function filter Evens

   filterEvens(myArray);

   return 0;

}

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