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abruzzese [7]
3 years ago
5

A laptop computer has two internal signals: An unplugged signal, which is '1' if the laptop's power supply is connected, and '0'

otherwise. A low battery signal, which is '0' if the laptop's battery has reached an almost empty state, and '1' otherwise. Suppose the laptop's power control system accepts a single hibernate signal which determines if the laptop should change its current operating state and shut down. If the laptop should shut down when the battery is low and its charger is unplugged, which gate could be used to produce the hibernate signal?
Computers and Technology
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

The correct usage is a NOR gate which is indicated in the explanation.

Explanation:

The truth table for the given two signals, namely

p=unplugged signal

q=low battery signal

can  form a truth table of following form

Here p has 2 states

1 if the power supply is connected

0 otherwise

Similarly q has 2 states

0 if the battery has reached almost zero state

1 otherwise

As the condition for the Hibernate Signal is given as to only activate when the battery is low and the power supply is not connected. This indicate that the value of Hibernate signal should be 1 when both p and q are 0.

Using this condition, the truth table is formed as

unplugged signal | low battery signal |  Hibernate Signal

            0               |                 0             |             1

            0               |                 1              |             0

            1                |                 0             |             0

            1                |                 1              |             0

Now the truth table of NOR is given as

a    |     b    |  a or b   |   ~(a or b)

0    |     0    |      0      |        1

0    |     1     |      1       |        0

1     |     0    |      1       |        0

1     |     1     |      1       |        0

This indicates that the both truth tables are same thus the NOR gate is to be used for this purpose.

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Def build_dictionary(string):
MissTica

Answer:

Follows are the code to this question:

def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter  

   d = dict()#defining d variable as a dictionary

   for x in string:#defining for loop that use string

       x = x.lower()#Use lower method  

       if not d.get(x):#defining if block that holds value in d variable

           d[x] = 1#use dictionary to hold value in 1

       else:#defining else block

           d[x] += 1#use dictionary to increment value by 1

   return d#return dictionary

print(build_word_counter(["Like","like","LIKE"]))#use print method to call method

def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable

   d = dict()#defining d variable as a dictionary

   for i in string:#defining for loop to count string value

       for j in i:#defining for loop to hold string as number

           if not d.get(j):#defining if block that doesn't get value in dictionary  

               d[j] = 1#hold value in dictionary  

           else:#defining else block

               d[j] += 1#use dictionary to increment the dictionary value

   return d#return dictionary

print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value

Output:

please find the attached file.

Explanation:

In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.

In the next step, a conditional statement is used that holds value in the dictionary and count its word value.

In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.

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Write a function `has_more_zs` to determine which of two strings contains # more instances of the letter "z". It should take as
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Answer:

// Method's name: has_more_zs

// Parameters are text1 and text2 to hold the two phrases to be tested

public static String has_more_zs(String text1, String text2) {

 // Create and initialize z1 to zero

 // Use z1 to count the number of zs in text1

 int z1 = 0;

 // Create and initialize z2 to zero

 // Use z2 to count the number of zs in text2

 int z2 = 0;

 

 //Create a loop to cycle through the characters in text1

 //Increment z1 by one if the current character is a 'z'

 int i = 0;

 while (i < text1.length()) {

  if (text1.charAt(i) == 'z' || text1.charAt(i) == 'Z') {

   z1 += 1;

  }

  i++;

 }

 //Create a loop to cycle through the characters in text2

 //Increment z2 by one if the current character is a 'z'

 

 i = 0; //Re-initialize i to zero

 

 while (i < text2.length()) {

  if (text2.charAt(i) == 'z' || text2.charAt(i) == 'Z') {

   z2 += 1;

  }

  i++;

 }

 

 

 //Using the values of z1 and z2, return the necessary statements

 if (z1 > z2) {

  return "The phrase '" + text1 + "'" + " has more occurences of z than the phrase " + "'" + text2 + "'";

 }

 else if (z1 < z1) {

  return "The phrase '" + text2 + "'" + " has more occurences of z than the phrase " + "'" + text1 + "'";

 }

 else if (z1 == z2) {

  return "The strings have the same number of z";

 }

 else {

  return "Neither string contains the the letter z";

 }

}

Explanation:

Explanation to answer has been given in the code as comments. Please refer to the comments for the details of the code.

The source code file has been attached to this response and saved as "NumberOfZs.java"

Hope this helps!

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