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Delicious77 [7]
2 years ago
7

When configuring an adsl installation where should you to install the dsl filters?

Computers and Technology
1 answer:
xxTIMURxx [149]2 years ago
5 0

<span>Filter installation in ADSL setup, the DSL filters should on connections leading to an analog phone. The DSL modem and phone were share on the same jack. ADSL is a type of digital subscriber line machinery, a data communication that enables faster data transfer over copper telephone lines.</span>

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Write any 2 differences between implicit variables and explicit variables.​Plz tell :' (
Marrrta [24]
Explicit is stated very clearly
Implicit is implied
Explicit leaves no room for confusion
Implicit doesn’t have to be directly stated
3 0
3 years ago
E-banking is also called: [1]
DENIUS [597]
Answer 1 it’s online banking
3 0
2 years ago
Topological sort requires only a tiny addition to the DFS algorithms. Exactly one of the following data structures is required t
Alekssandra [29.7K]

Answer:

Stack.

Explanation:

Topological sort requires a bit of addition to DFS algorithm.So DFS can be done by two ways that are either you can use recursion or you can use Stack data structure to implement DFS.

Since recursion uses stack memory when it makes recursive calls and if you want to do it iteratively you can stack data structure.

8 0
3 years ago
Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?
frutty [35]

Answer:

The root is:

c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

%        - err is the stimated error for  c

ya = feval(f, a);

yb = feval(f, b);

if  ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if  yc == 0

 a = c;

 b = c;

elseif  yb*yc > 0

 b = c;

 yb = yc;

else

 a = c;

 ya = yc;

end

if  b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

   1.5708

err =

  5.8208e-11

yc =

 -3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0
3 years ago
Lisa granted the CREATE TABLE privilege WITH ADMIN OPTION to Sharon. Sharon granted the privilege to Bob. If Lisa’s privileges a
GuDViN [60]

Answer:

D

Explanation:

As it's not fair if they all lose there privileges

4 0
3 years ago
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