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o-na [289]
3 years ago
11

HELP! PLEASE DONT NEED TO SHOW WORK! NO FALSE ANSWERS

Mathematics
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

A. 12.

Step-by-step explanation:

In a 30-60-90 triangle the ratio of  the shortest leg to the hypotenuse is 1:2.

So here the hypotenuse = 2*6 = 12 units long.

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Can I have help with these? Picture attached.
8_murik_8 [283]

Answer:

5. mCD is 27.8°  |  7. mAFC 52.3° |

Step-by-step explanation:

8 0
3 years ago
On the observation platform in the crown of the Statue of Liberty, Miguel is approximately 250 ft above ground. He sights a ship
Basile [38]

Answer:

Let the distance from the base of the statue to the ship be d, then

tan 18 = 250/d

d = 250 / tan 18 = 769.4

The distance from the base of the statue to the ship to the nearest foot is 769 feet.

Step-by-step explanation:

3 0
3 years ago
For this problem, for finding the slope, I need help with this.
Elena-2011 [213]

Answer: the slope is 1

Step-by-step explanation:

Slope = Rise over Run. Rise= y run= x

For this problem the rise is the difference between 3 and 1 and the run is the difference between 0 and -2. The difference between 3 and 1 is 2 and the difference between 0 and -2 is also too. Which makes it 2/2 which simplifies to 1.

4 0
3 years ago
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
#16 and #20! Please help!!!
Ilia_Sergeevich [38]
Well idk about #16 but #20 I can answer it OK look, number 20 , Y represent height X represent time OK, number a is asking for maximum height , the ball will reach the maximum height when time equal zero so Y = -16(0)^2 + 15(0) + 6 which equals 6 so maximum height is 6 feet, and as for number b , when the ball hit the ground the distance will equal zero so Y = 0 , so by factorizing. the given equation find the values of X, U will probably find 2 values one in +ve and one in -ve take the positive and neglect the -ve and we are done
7 0
3 years ago
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