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Rama09 [41]
1 year ago
10

A satellite travels from Earth to the moon (238,905 miles), then from the moon to Mars (48,340,732 miles) and finally from Mars

to Venus (71,948,832 miles). How far did the satellite travel in all?
Mathematics
1 answer:
hodyreva [135]1 year ago
8 0

The total distance the satellite traveled in all is 120,528,469 miles

<h3>Calculating total distance</h3>

From the question, we are to determine how far the Satellite traveled in all

From the given information,

A satellite travels from Earth to the moon (238,905 miles),

and

It traveled from the moon to Mars (48,340,732 miles)

and

It finally traveled from Mars to Venus (71,948,832 miles)

The total distance the satellite traveled in all = 238,905 miles + 48,340,732 miles + 71,948,832 miles

∴The total distance the satellite traveled in all = 120,528,469 miles

Hence, the total distance the satellite traveled in all is 120,528,469 miles

Learn more on Calculating distance here: brainly.com/question/24295081

#SPJ1

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Quadrilateral ABCD is dilated by a scale factor of 1 over 3 centered around (1, 2). Which statement is true about the dilation?
Sonbull [250]

<em>Note: Since you missed to add the figure. So, after a little research I am kind of able to find the figure and hence, assuming it as a reference. Hence, I am attaching the figure and solution of that figure is also visible in the same figure.</em> Please check the attached figure (a)

Answer:

Segment B'D' will be parallel to segment BD and will be shorter than segment BD. Please see the attached figure (a) for better understanding.

Step-by-step explanation:

As we know that there are certain rules when a quadrilateral is dilated by a certain scale centered around a certain point.

So,

Let suppose P(a, b) is the point.

The dilation rule by a scale factor of 1 over 3 or (1/3) centered around (1, 2) is

P(a, b) → P(\frac{x+2}{3}, \frac{y+4}{3})

Hence,

            A(1, 2) → A'(1, 2)

            B(2, 3) → B'(4/3, 7/3)

            C(4, 2) → C'(2, 2)

             D(2, 1) → D'(4/3, 5/3)

The attached figure show that if we draw the all these points in the coordinate plan i.e. A(1, 2), B(2, 3), C(4, 2), D(2, 1) and A'(1, 2), B'(4/3, 7/3), C'(2, 2), D'(4/3, 5/3), we can determine that Segment B'D' will be parallel to segment BD and will be shorter than segment BD.

<em>Keywords: dilation, quadrilateral, segment</em>

<em> Learn more about dilation from brainly.com/question/7569824</em>

<em> #learnwithBrainly</em>

7 0
3 years ago
On a trip to Florida, Santina drove 203 miles and Carole drove 189 miles. How many more miles did Santina drive than Carole?
matrenka [14]

Answer:

1. santina drove 14 more miles than carole

2. the owner will need to buy 8 bags this week

Step-by-step explanation:

1. 203-189= 14

2. if they use 80 pounds a week and can only buy 10 pounds in one bag, they'll need 8 bags to equal 80 pounds since each bag is 10 pounds

3 0
2 years ago
VALUE<br> RATIONAL OR IRRATIONAL?<br> 1.<br> 55<br> 2. V126<br> 5. 0.7
neonofarm [45]

Answer:

1 rational

2 . irrational

3 irrational

4 rational

5 rational

4 0
3 years ago
Help me please. 30 points :)
Nataly [62]

\frac{(5 \:  -  \: 8x)}{( \sqrt{5 \:  -  \: 8x} )}  \:  =  \:  \sqrt{5 \:  -  \: 8x}
For the result to be Real,
5 \:  -  \: 8x \:  \geqslant  \: 0
8x \:  \leqslant  \: 5
x \:  \leqslant  \:  \frac{5}{8}
( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \:  \times  \:  (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \:  =  \:  \frac{ {(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
Hence,
\frac{{(5 \:  -  \: 8x)}^{ \frac{3}{2} } }{(5 \:  -  \: 8x)}
is the required form.

3 0
3 years ago
I Don't get it......​
Lemur [1.5K]
I think you clicked on the correct answer! Correct me if I’m wrong!
3 0
3 years ago
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