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Sholpan [36]
3 years ago
8

Step-by-step how-to evaluation

Mathematics
2 answers:
lina2011 [118]3 years ago
6 0
First, we can use distribution property to simplify the expression.

Distribution property
\boxed{a(b+c) = ab+ac}

126( \frac{8}{9}+ \frac{x-4}{7} )
=126( \frac{8}{9} )+126( \frac{x-4}{7})
= \frac{126(8)}{9} + \frac{126(x-4)}{7}


Second, simplify the numerator and the denominator
Because the numerator (126) and the denominator (9) on the first term has 9 as the greatest common factor, divide the numerator and the denominator by 9.
= \boxed{\frac{126(8)}{9}} + \frac{126(x-4)}{7}
= \boxed{\frac{14(8)}{1}} + \frac{126(x-4)}{7}
= 14(8) + \frac{126(x-4)}{7}

Because the numerator (126) and the denominator (7) on the second term has 7 as the greatest common factor, divide the numerator and the denominator by 7.
=14(8) + \boxed{\frac{126(x-4)}{7}}
=14(8) + \boxed{\frac{18(x-4)}{1}}
=14(8)+18(x-4)


Third, simplify the first term by multiplication, simplify the second term by distribution property
= 14(8) + 18(x - 4)
= 112 + 18(x - 4)
= 112 + 18x - 18(4)
= 112 + 18x - 72

add the constant (112) with the other constant (-72)
= 18x + 112 - 72
= 18x + 40


<u>This is the simplest expression</u>
\boxed{18x+40}
Orlov [11]3 years ago
3 0
Least common multiple=lcm
lcm(9,7)=63

126(8/9  +  (x-4)/7 )=
126(7*8+9(x-4)/63=
126(56+9x-36)/63=
126(20+9x)/63=                      (126/63=2)
2(20+9x)=
40+18x

Answer: 126(8/9  +  (x-4)/7 )=  40+18x
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Answer:

See explanation below for further details.

Step-by-step explanation:

A rational consist of two real numbers such that:

\frac{a}{b} =c

If c is a polynomial with a certain grade, then, both the numerator and the denominator must be also polynomials and the grade of the numerator must be greater than denominator.

If c is linear function, that is, a first order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.

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If a = x^{2} and b = x, then:

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It is worth to add that exponential functions can be a linear combination of single exponential function, similar to polynomials.

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