Carlos has 4 fifths of a tank of fuel in his car. He uses 1 tenth of a tank per day. How many days will his fuel last?
2 answers:
4 fifths and 1 tenth can be represented as fractions.
4/5 and 1/10
To find out how much he uses per day, we must subtract 4/5 from 1/10. BUT, before we do that, we must create a common denominator.
1/10 cannot be reduced, but 4/5 can be multiplied by 2 to make 8/10.
Now we can perform our equation:
He would have 7/10 of gas left after one day. If this went on, his fuel would last for 8 total days.
4/5 and 1/10
To find out how much he uses per day, we must subtract 4/5 from 1/10. BUT, before we do that, we must create a common denominator.
1/10 cannot be reduced, but 4/5 can be multiplied by 2 to make 8/10.
Now we can perform our equation:
He would have 7/10 of gas left after one day. If this went on, his fuel would last for 8 total days.
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Answer:
The common ratio of a geometric series is \dfrac14
4
1
start fraction, 1, divided by, 4, end fraction and the sum of the first 4 terms is 170
The first term is 128
Step-by-step explanation:
The common ratio of the geometric series is given as:
The sum of the first 4 term is 170.
The sum of first n terms of a geometric sequence is given b;
common ratio, n=4 and equate to 170.