Answer:
5
Step-by-step explanation:
If you can buy one for $4
20/4 = 5
you can buy 5 cans
First restaurant price: 29 + 6l = x
x = final cost
l = kilo of lobster
Second restaurant price: 41 + 3l = x
We want them to be the same price, so: 29 + 6l = 41 + 3l
Subtract 3l from each side
29 + 3l = 41
Subtract 29 from both sides
3l = 12
Divide both sides by 3
l = 4
So, if she buys 4 kilograms of lobster from either place, it will cost the same.
It would cost $53.
Answer:
The slope is 
$0.1774 / pounds
Step-by-step explanation:
From the question we are told that
The weight of the rat is 
The cost of feeding the rat per week is 
$4.50
The weight of a Beagle is 
The cost of feed a Beagle per week is 
$9.20
Now the slope can be evaluated mathematically as
substituting values
$0.1774 / pounds
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
Answer:
$48.5
Step-by-step explanation:
There are ten children and the total made is $485. So:
485/10 = $48.5
