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Kitty [74]
2 years ago
13

Find the rate of change from the given table.

Mathematics
1 answer:
Ymorist [56]2 years ago
4 0
The rate of change would be D. 4
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Please help me..please
myrzilka [38]
Why are you asking me for help
6 0
3 years ago
Rearrange x = 3g + 2 to make g the subject.
Kisachek [45]

Answer:

g = \frac{x-2}{3}

Step-by-step explanation:

x = 3g + 2 ( subtract 2 from both sides )

x - 2 = 3g ( divide both sides by 3 )

\frac{x-2}{3} = g

5 0
1 year ago
Read 2 more answers
In a first-order decomposition reaction. 52.3% of a compound decomposes in 8.6 min. How long (in min) does it take for 80.3% of
rusak2 [61]

Answer:

13.20 min

Step-by-step explanation:

Rate of the reaction is a measure of the rate of decomposition of the compound.

Rate (R) = Concentration (C) ÷ time (t)

C1/t1 = C2/t2

C1 = 52.3% = 0.523

t1 = 8.6 min

C2 = 80.3% = 0.803

t2 = C2t1/C1 = 0.803×8.6/0.523 = 13.20 min (to 2 decimal places)

7 0
3 years ago
What is the exact volume of the cone?<br><br> H = 6 cm<br> R = 9 cm
faltersainse [42]

Answer:

508.68 or 508.7

Step-by-step explanation:

V=1/3(3.14)(9)^2(6)

(3.14)(81) x 6

(3.14)(486)

1/3(1526)

(divide by 3)= 508.68

6 0
3 years ago
b) If parametric equations of a flow line are x = x(t), y = y(t), explain why these functions satisfy the differential equations
sineoko [7]

Answer:

The equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1.

Step-by-step explanation:

The pathline equation for a vector field is given by F(x,y) = xî - yj

The velocity vector field for the streamline of the flow is given by

V(x, y) = (dx/dt)î + (dy/dt)j

From the question, it is given that

(dx/dt) = x

(dy/dt) = -y

Hence, the velocity vector field for the streamline of the flow in question is

V(x, y) = xî - yj

which coincides with the pathline vector field of the flow.

The only time the pathline and streamline vector field coincide and have the same equation is when the flow is a steady state flow.

That is, the properties of the fluid flowing isn't changing with time!

Hence, this flow is a steady state flow!

We're told to solve the differential equation.

(dx/dt) = x

(dy/dt) = -y

but

(dy/dx) = (dy/dt) × (dt/dx)

(dy/dx) = -y/x

(dy/y) = -(dx/x)

∫(dy/y) = -∫ (dx/x)

In y = - In x + c

where c is the constant of integration

In y + In x = c

In (xy) = c

Inserting the values of (x, y) given in the question,

In (-1 × -1) = c

In 1 = c

0 = c

c = 0

In y + In x = 0

In (yx) = 0

xy = e⁰ = 1

xy = 1

So, the equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1

Hope this Helps!!!

4 0
3 years ago
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