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gladu [14]
3 years ago
11

Eric Bella Joan or Maya PLEASE HELP

Mathematics
1 answer:
TEA [102]3 years ago
3 0
Joan did 21 is not a prime number good luck!!!
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Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?
Mashutka [201]
M=0 i am not sure it is right 
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3 years ago
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Question 6 (4 points)
riadik2000 [5.3K]

Answer:

Interior Angles: 3, 4, 5, 6

Exterior Angles 1, 2, 7, 8

Hope this helps!

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Can someone please answer. There is one problem. There's a picture. Thank you!
allochka39001 [22]
\dfrac{60^o}{360^o}=\dfrac{1}{6}\\\\A_O=\pi\cdot4^2=16\pi\\\\Area\ of\ the\ shaded\ sector:\\\\A=\dfrac{1}{6}\cdot16\pi=\dfrac{8}{3}\pi\approx\dfrac{8}{3}\cdot3.14\approx8.4\\\\Answer:\boxed{8.4}
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3 years ago
25 POINTS
uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)


Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0
3 years ago
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What’s the answer in neeeeeeeeed it………
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Answer:

10x

Step-by-step explanation:

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