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3 years ago

How does one deal with inequalities again?

Mathematics

1 answer:

postnew [5]3 years ago

4 0

You put the numbers you want to compare in a line with a space in the middle. the put
$>$
if the left is bigger and
$<$
if the right side is bigger.

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Which is smaller-21/35, 7/5

Paladinen [302]

Answer:

-21/35

Step-by-step explanation:

So, 7/5 is a postive number, since it doesn't have a negative - sign in front of it. On the other hand, -21/35 does. Knowing this, we can conclude that -21/35 is smaller than 7/5.

If you want another way of thinking about it, just guessing, what is 7/5? Well, 7 is bigger than 5, so it must be at least 1. On the other hand, with -21/35, the -21 doesnt look like its bigger than 35, so it must be smaller than 1.

Answer:

-21/35 is smaller than 7/5

Ti⊂k∫∈s ω∅∅p

3 0

3 years ago

Read 2 more answers

What is the length of segment XY? 4.5 units /45 units /53 units 9 units

noname [10]

It might be √53 because they are 7 squares away from each other ( I have the same question ) but Im not 100% sure..

8 0

3 years ago

Read 2 more answers

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago

A,B,C,D are 4 towns. B is 40 kilometeres due east of A. C is 30 kilometeres due north of A. D is 45 kilometeres due south of A.

Vesna [10]

Answer:

Step-by-step explanation:

The diagram illustrating the scenario is shown in the attached photo.

We would determine angle ACB by applying the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Taking angle ACB as the reference angle,

Tan C = 40/30 = 1.33

Angle ACB = tan^-1(1.33) = 53.1°

The bearing is calculated with respect to the northern direction. Therefore, the bearing of B from C is

180 - 53.1 = 126.9°

4 0

3 years ago

I need help asap!

k0ka [10]

Answer:

AC and BC are $3\sqrt{2}$ or 4.24

Step-by-step explanation:

AC=BC and AB = 6 units

Let AC=BC=x units

$AB^2=AC^2+BC^2\\6^2=x^2+x^2\\6^2=2x^2$ $36=2x^2\\x^2=18\\x=\sqrt{18} =3\sqrt{2}$

6 0

3 years ago