All categories

3 years ago

What the slope (0,-1) and (2,-5)

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

5 0

In this question, you're trying to find the slope with the given coordinates.

To find the slope, you would use the slope formula.

Slope formula:

$\frac{y2-y1}{x2-x1}$

Plug in the coordinates to its right values and solve.

$\frac{-5+1}{2-0}\\\\\frac{-4}{2}\\$

Now simplify by dividing by two.

$-2$

When you're done solving, you would get "-2" as your answer.

This means that your slope would be -2

Answer:

-2

34kurt3 years ago

3 0

Answer:

-4/2, or finding slope is (difference of y)/(difference of x) inserting those numbers into the equation would be (-5-(-1))/(2-0), which would become -4/2, which is basically -2.

You might be interested in

Find the mean, median, and mode of the data set. Round to the nearest tenth.

statuscvo [17]

The mean is the average of the data set. Median is the value that separates the higher half and the lower half of the set of values. Mode is the value that occurs often in the data set. Therefore, the correct answer is option A, <span>mean = 9.7, median = 10, mode = 15</span>

6 0

3 years ago

Read 2 more answers

How do i solve for x if 6x - 6 - 7x =6

Dmitry_Shevchenko [17]

Answer:

X = 12

Step-by-step explanation:

Step 1 :

Pulling out like terms :

1.1 Pull out like factors :

-x - 12 = -1 • (x + 12)

Equation at the end of step 1 :

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : -x-12 = 0

Add 12 to both sides of the equation :

-x = 12

Please said thanks

7 0

3 years ago

Read 2 more answers

What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

zhannawk [14.2K]

Answer:

$- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$

Step-by-step explanation:

We have to find the quotient of the following division, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$ .

Now, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$

= $- \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]}$ {Since all the terms in the expression are in product form, so we can treat them separately}