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GrogVix [38]
3 years ago
12

A machine in a chocolate factory is set to squirt out a predetermined amount of molten chocolate. When the machine is set to x,

the drop of molten chocolate will be x grams with a standard deviation of 0.01 grams. Suppose you know that nearly all the chocolate chips produced will have a mass within 2 standard deviations of the mean. If you want to minimize the number of chocolate chips that are less than 2 grams, what is the lowest setting of x you should set the machine to
Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

Sorry I need Points but I also need help

Step-by-step explanation:

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A 2000 gallon fish aquarium can be filled by water flowing at a constant rate in 10 hours. When a decorativve rock is placed in
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Answer:

The volume of the rock is 13.368 cubic feet.

Step-by-step explanation:

The volume of the rock (V_{r}), measured in gallons, is equal to the volume of the fish aquarium without the decorative rock (V') minus the volume of the fish aquarium with the decorative rock (V''), both measured in gallons.

Since the water flow is at constant rate, the volume of the rock is expressed by the following equation:

V_{r} = V' - V''

V_{r} = \dot V \cdot (\Delta t_{1}-\Delta t_{2}) (1)

Where:

\dot V - Flow rate, measured in gallons per hour.

\Delta t_{1} - Filling time of the fish aquarium without the decorative rock, measured in hours.

\Delta t_{2} - Filling time of the fish aquarium with the decorative rock, measured in hours.

And the flow rate is:

\dot V = \frac{2000\,gal}{10\,h}

\dot V = 200\,\frac{gal}{h}

The flow rate is 200 gallons per hour.

If we know that \dot V = 200\,\frac{gal}{h}, \Delta t_{1} = 10\,h and \Delta t_{2} = 9.5\,h, then the volume of the rock is:

V_{r} = \left(200\,\frac{gal}{h}\right)\cdot (10\,h-9.5\,h)

V_{r} = 100\,gal

V_{r} = 13.368\,ft^{3}

The volume of the rock is 13.368 cubic feet.

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If there are 5 specific spots and the order does matters then we would have:

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