Answer:
look down there
Step-by-step explanation:
First ball:
Probability of drawing a white ball is 5/8
Probability of drawing a black ball is 3/8
Second ball:
This depends on the first ball drawn, lets say you drew a white ball initially, 4 white balls are left out of 7 balls in total. The probability of a white ball in the second pick is 4/7.
Total probability of drawing two white balls is 5/8*4/7 (since they are independent events).
If you picked a black ball initially, picking another black ball would have a probability of 2/7, on similar grounds , total prob for 2 blacks would be 3/8*2/7.
The probability that you pick 2 balls of same color is (5/14 + 3/28) = 13/28. (Since they are mutually exclusive events)
Answer:
5
Step-by-step explanation:
4(5+n)=4(n+p)
20+4n=4n+4p
4p=20
p=20/4
p=5
Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))
