Ask question

Ask question

All categories

2 years ago

11

Can someone help me out please

1 answer:

ArbitrLikvidat [17]2 years ago

6 0

B) AAS Congruence Theorem
(correct answer i promise)

explanation:
The Angle Angle Side postulate (often abbreviated as AAS) states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.

You might be interested in

To eliminate 6X you would Transform 2x by multiplying what number ?

NARA [144]

Answer:

-3

Step-by-step explanation:

to eliminate 6x we need the same no. 6x but that should be negative. so

2X × -3 = -6X

and

6X+(-6X)=0

5 0

3 years ago

What is 19.6 divided by 7

Lemur [1.5K]

19 divided by 7 = 2.8

7 0

3 years ago

Find the value of x in the following..... 3^x = 8

elena-14-01-66 [18.8K]

Find logarithm of both sides

log (3^x) = log 8

xlog3 = log8

x = log8/log3

x = 1.893

7 0

3 years ago

Read 2 more answers

Solve the equation for all values of x in simplest form:<br> (x - 2)2 = 49

marin [14]

2x-4=49
2x=54
x is equal to 27

3 0

3 years ago

Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t

julsineya [31]

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , $n(C \cap D)$ = 12%

Percentage who had neither cats nor dogs, $n(C \cup D)'$ =45%

Now:

Universal Set, $U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'$

$100 = 40 + n(D)-12+45\\n(D)=100-73\\$Percentage of those who own dogs =27\%$

Therefore:

Number of Students who had dogs

=27% of 300

=81

3 0

3 years ago