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3 years ago

10

Sandra plans to excersise the same number of minutes m each of the remaning three days this week in order for sandra to excersis

e for exactly 150 minutes this week what is the
value of m

1 answer:

aleksandrvk [35]3 years ago

3 0

I think its 350 because 150x the three days =350

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Step-by-step explanation:

Do you would take 500 times 16. 6 times 0 is 0, do that one more time until you’re at the 5. So, 6 times 5 is 30. Put the 3 over the 5 and the 0 under the line. Drop a 0 and do 1x0 twice. 1x5 is five. Plus 3 is 8. Add all of the numbers together, getting the number of 8,000!

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You have a fishing line spool with an end that has an area of 20.0 cm2. How much fishing line do you need to wind around the spo

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<h3>Problem Solution</h3>

Assuming the spool is a cylinder and the circumference we're winding around is that of a circle with the given area, we can write the relation between circumference and area as

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

So

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

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I hope it helps!

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3 years ago