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dexar [7]
3 years ago
8

{x}^{2} + 5x - 6" align="absmiddle" class="latex-formula">
- ری​
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0
<h2>Simplify:</h2>

Step-by-step explanation:

\ Given \ that:\\\\\ x^2 \ + 5\ x -6\\\\\ Solution: \\\\\ First \ calculate \ factor :\\\\\rightarrow \ x^2 \ + 5\ x -6\\\\\therefore  \ first \ calculate \ factor \ that \ is \ 6 \ - 1\ = 5\\\\\rightarrow \ x^2 \ + (6-1)\ x -6\\\\\rightarrow \ x^2 \ + 6x-1x -6\\\\\rightarrow \ x(x + 6)-1(x+6)\\\\\rightarrow \ (x + 6) (x-1)\\\\

Learn more:

  • Simplify: https://brainly.in/question/13979352
Ymorist [56]3 years ago
7 0

Answer:

(x+6)(x-1)

Step-by-step explanation:

factor using the x-box method

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Given g (x)=-x^2+10x-3<br> Find g (-3)
sweet-ann [11.9K]

Answer:

The value of g(x) at x=-3 is -42

That is g(-3)=-42

Step-by-step explanation:

Given that the function g is defined by g(x)=-x^2+10x-3

To find the value of g(-3) :

That is to find the value of g(x) at x=-3 :

g(x)=-x^2+0x-3

Put x=-3 in the above function we get

g(-3)=-(-3)^2+10(-3)-3

=-(9)-30-3

=-9-33

=-42

Therefore g(-3)=-42

The value of g(x) at x=-3 is -42

That is g(-3)=-42

3 0
3 years ago
I know I’m supposed to use the formula A= L•W
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GaryK [48]
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In sondras math class the teacher gives all of the students the digram below where ab is perpendicular to bc and ac is perpendic
TEA [102]
<span>Given the set up of the diagram, AB^2 will equal AC x AD and BC^2 will equal AC x DC. To solve, substitute AB^2 + BC^2 with (AC x AD) + (AC x DC). Then, take out like terms through the distributive property: AC (AD + DC). AD + DC is equal to AC. So, AC x AC = AC^2.</span>
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