Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( 
) & ( 
)-
y - 
= 
( x - 
)
i.e. <em> y - 7= 
( x- 1)</em>
<em> y - 7 = 
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
Choice 3: AAS
Step-by-step explanation:
We can prove that by AAS that means we need two congruent angles and one congruent side.
The first angle will be the vertical pair <FBG and <DBC.
The second angle will be the alternate interior pair <G and <D.
The one side will be 
and 
.
Answer: the answer would be choice A
Step-by-step explanation: it passes through the origin making it a proportional relationship
