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Afina-wow [57]
3 years ago
13

Evaluate (9^-3)(9^12)

Mathematics
2 answers:
frutty [35]3 years ago
7 0

Answer:

1/9^3(9^12)

9^12/9^3

9^12-3

9^9

397,420,489

Tema [17]3 years ago
4 0

9514 1404 393

Answer:

  387,420,489

Step-by-step explanation:

The order of operations tells you that exponential terms must be evaluated first, before multiplication:

  (9^-3)(9^12) = (1/729)(282,429,536,481) = 387,420,489

__

The rules of exponents tell you that this can be simplified before it is evaluated.

  (9^-3)(9^12) = 9^(-3+12) = 9^9 = 387,420,489

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amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

6 0
3 years ago
11z/16+7z/8=5/16 as a decimal
babunello [35]
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if f is a differentiable function and f(0)=-1 and f(4)-3 then which of the following must be true there exists a c in [0,4] wher
iragen [17]

Answer:

True, see proof below.

Step-by-step explanation:

Remember two theorems about continuity:

  1. If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
  2. (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.

If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.

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3 years ago
Given: B bisects EA, FE is parallel to CA, DC is parallel
SIZIF [17.4K]

Answer:

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Step-by-step explanation:

We can prove that by AAS that means we need two congruent angles and one congruent side.

The first angle will be the vertical pair <FBG and <DBC.

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