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JulijaS [17]
4 years ago
14

To create a nonlinear presentation that had external links the designer should

Computers and Technology
1 answer:
laila [671]4 years ago
6 0

Answer:

To create a nonlinear presentation that had external links the designer should include “hyperlinks”

Explanation:

Let us understand what non-linear presentation is. It’s a reverse of linear presentation. A linear will go slide by slide, without any jump. A non-linear slide is a type of presentation prepared when the flow of slide is not much important, and the presenter can jump to any of the slide from any slide. This is done thorough two ways. 1. Hyperlink 2. Action button

We must include hyperlinks or action buttons where it allows us to toggle or navigate to any of the slide within the file. The hyperlink can also be added to move the control to a website.

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Which of the following Web 2.0 tools can aid in searches using key words? (1 p
svet-max [94.6K]

Web 2.0 Tools can aid in searches using key words

Explanation:

Web 2.0 Tools can aid in searches using key words .The followings are some tool like face book and you tube and google search that allow users to searches using key words. web 2.0 tools can be used to teach curriculum content, store data, create and edit video, edit photos,etc.,

Web 2.0 tools are easy to use websites designed to encourage creativity, team work, also helps in higher order thinking skills in classroom .The important thing is to teach students to think critically with whatever tools they have in front of them using key words while searching.

3 0
3 years ago
What is used in an ipv6 for local device to learn the layer 2 ethernet address of a device that is on a remote nonlocal vlan?
zavuch27 [327]
The devices in IPv6 only need to learn the Layer 2 Ethernet address of a neighbor that is directly connected, and only if they need to communicate with each other on that local network. If the device you are trying to connect to is remote, you will forward the packet to your default gateway’s Layer 2 address.
NDP (Neighbor Discovery Protocol) is used to learn local neighbors’ Layer 2 Ethernet addresses when needed.
ARP is an IPv4 method to learn a local device’s Layer 2 address.
The RIPng (RIP next generation) is RIP version that support of IPv6 networking..
3 0
4 years ago
Case 9-2 Gracie is trying to decide between Windows or macOS for her new desktop computer. Since you have desktops that run both
MrMuchimi

Answer:

Finder

Explanation:

The Finder is the default file manager and graphical user interface shell used on all Macintosh operating systems. Described in its "About" window as "The Macintosh Desktop Experience", it is responsible for the launching of other applications, and for the overall user management of files, disks, and network volumes.

- this seems very course reliant, refer to your course if this is not the answer you were looking for.

3 0
3 years ago
Write an application that solicits and inputs three integers from the user and then displays the sum, average, product, smallest
Oksana_A [137]

Answer:

Please find below program

Explanation:

import java.util.Scanner;

public class Tester {

public static void main(String[] args) {

 

 // create an object of scanner class

 Scanner scanner  = new Scanner(System.in);

 

 //prompt user to enter first number

 System.out.println("Enter first integer: ");

 

 // read value from entered by user and keep it in num1

 int num1 = scanner.nextInt();

 

 //prompt user to enter second number

 System.out.println("Enter second integer: ");

 

 // read value from entered by user and keep it in num2

 int num2 = scanner.nextInt();

 

 //prompt user to enter third number

 System.out.println("Enter third integer: ");

 

 // read value from entered by user and keep it in num3

 int num3 = scanner.nextInt();

 //close scanner as we have done with user input

 scanner.close();

 

 //calculate sum

 int sum = num1+num2+num3;

 

 //calculate average

 int average = sum/3;

 

 //calculate product

 int product = num1*num2*num3;

 

 //find out largest number

 int largest = 0;

 if (num1>=num2){

  if(num1>=num3)

   largest = num1;

  else

   largest = num3;

 }else {

  if(num2>=num3)

   largest = num2;

  else

   largest = num3;

 }

 

 // find out smallest number

 int smallest = 0;

 if (num1<=num2){

  if(num1<=num3)

   smallest = num1;

  else

   smallest = num3;

 }else {

  if(num2<=num3)

   smallest = num2;

  else

   smallest = num3;

 }

 

 // print all the information

 System.out.println("Sum of three numbers : "+sum);

 System.out.println("Product of three numbers : "+product);

 System.out.println("Average of three numbers : "+average);

 System.out.println("Smallest number : "+smallest);

 System.out.println("Largest number : "+largest);

}

}

3 0
4 years ago
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