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bulgar [2K]
3 years ago
7

A cyclist bikes at a constant speed for 22 miles. He then returns home at the same speed but takes a different route. His return

trip takes one hour longer and is 27 miles. Find his speed
Mathematics
1 answer:
brilliants [131]3 years ago
4 0
How concerned are you with how to get the answer?
Because I know the answer is 5 miles per hour
22/5= 4.4 hours
27/5= 5.4 hours

Alright this is how you solve it
Distance over time equals speed
So 22/y=x and 27/y+1=x
Start by solving for time by having these two equations equal each other
22/y=27/y+1
Cross multiply to get
22(y+1)=27y
22y+22=27y
Isolate Y
5y=22
Y=4.4
Now solve for X which is the speed, you can plug in Y to either of the two equations
22/4.4=x
X=5 miles per hour
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6y + 2 + 3 + 14y
hichkok12 [17]

Answer:

20y + 5

Step-by-step explanation:

6y + 2 + 3 + 14y

20y + 2 + 3

20y + 5

Have an amazing day!

PLEASE MARK BRAINLIEST!

3 0
2 years ago
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Fowle Marketing Research Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean tim
sergejj [24]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958      

c) p_v =P(t_{34}>2.958)=0.0028    

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

The sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And the sample deviation is:

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=17 represent the sample mean    

s=4 represent the sample standard deviation

n=35 sample size  

\mu_o =15 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less or equal than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

Since we don't  know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{17-15}{\frac{4}{\sqrt{35}}}=2.958  

Part c P-value  

The degrees of freedom are given by:

df = n-1= 35-1=34

Since is a right tailed test the p value would be:  

p_v =P(t_{34}>2.958)=0.0028  

Part d Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 1% of signficance.  

7 0
3 years ago
( 16.9 - 5.47 ) x 7.09 plzz i want with full solution
Mila [183]

Answer:

81.03

Step-by-step explanation:

(16.9-5.47)×7.09

(11.43)×7.09

81.0387

OR

81.03

HOPE THIS HELPS YOU

8 0
2 years ago
A recent research study randomly divided participants into groups who were given different levels of Vitamin E to take daily. On
horrorfan [7]

Answer: D. To produce treatment groups with similar characteristics

Step-by-step explanation:

By using randomization in sampling, the Sample would be more representative of the Population it is based off of because different demographic characteristics may be picked.

This leads to a situation where the groups have similar characteristics between themselves thereby making it easier for comparison. For example, Group 1 would have certain types of people that will be represented in Group 2 and Group 3 as well. That way the effects of the drug can be properly studied as it affects different people. For instance, say there are 4 obese people in a sample of 10, instead of group one having all obese people, randomization may be able to give group one, 2 obese people and 2 obese people to group 2 as well. That way when comparing, the effects of the drug on the two groups is easier to be compared because the two groups have similar people.

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U can show your work by underlining what your rounding and showing which place it is it the right of it but there is no mathematical work
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