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-Dominant- [34]
3 years ago
8

How to calculate the measure of center with an example question

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

3

Step-by-step explanation:

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The course grade in a statistics class is the average of the scores on five examinations. Suppose that a student's scores on the
nadya68 [22]

Answer:

84 is the highest possible course average

Step-by-step explanation:

Total number of examinations = 5

Average = sum of scores in each examination/total number of examinations

Let the score for the last examination be x.

Average = (66+78+94+83+x)/5 = y

5y = 321+x

x = 5y -321

If y = 6, x = 5×6 -321 =-291.the student cannot score -291

If y = 80, x = 5×80 -321 =79.he can still score higher

If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.

If y= 100

The average cannot be 100 as student cannot score 179(maximum score is 100)

8 0
2 years ago
The graph shows the functions f(x), p(x), and g(x): Graph of function g of x is y is equal to 1 plus the quantity 1.5 raised to
satela [25.4K]
Part A:

Given that the <span>straight line p(x) joins the ordered pairs (0, 2) and (1, -5), thus the equation of the line joining ordered pairs (0, 2) and (1, -5) is given by

\frac{y-2}{x} = \frac{-5-2}{1} =-7 \\  \\ \Rightarrow y-2=-7x \\  \\ \Rightarrow y=-7x+2

Thus, p(x) = -7x + 2

</span>Given that the <span>straight line f(x) joins the ordered pairs (4, 1) and (2, -3), thus the equation of the line joining ordered pairs (4, 1) and (2, -3) is given by

\frac{y-1}{x-4} = \frac{-3-1}{2-4} =\frac{-4}{-2}=2 \\  \\ \Rightarrow y-1=2(x-4)=2x-8 \\  \\ \Rightarrow y=2x-7

Thus, f(x) = 2x - 7
</span>
The solution to the pair of equations represented by p(x) and f(x) is given by

p(x) = f(x)
⇒ -7x + 2 = 2x - 7
⇒ -7x - 2x = -7 - 2
⇒ -9x = -9
⇒ x = -9 / -9 = 1

Substituting for x into p(x), we have

p(1) = -7(1) + 2 = -7 + 2 = -5

Therefore, the solution to the pair of equations represented by p(x) and f(x) is  (1, -5)



Part B:

From part A, we have that f(x) = 2x - 7

when x = -8

f(-8) = 2(-8) - 7 = -23

Thus, (-8, -23) is a solution to f(x).

When x = -10

f(-10) = 2(-10) - 7 = -27

Thus, (-10, -27) is a solution to f(x).

Therefore, two solutions of f(x) are (-8, -23) and (-10, -27).



Part C:

From part A, we have that p(x) = -7x + 2, given that g(x) = 1 + 1.5^x

From the graphs of p(x) and g(x), we can see that the two graphs intersected at the point (0, 2).

Therefore, the solution to the equation p(x) = g(x) is (0, 2).

3 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
A bag of oranges weighs 5 1/4 pounds. How much does 1 1/2 bags weigh?
Andreyy89

Answer:

you simplify the fractions then you cross multiply

Step-by-step explanation:

1/2 * 4/2 you multiply 1 and 4 and you get 4/4 which is equal to 1  

3 0
3 years ago
Rearrange w= 3(2a + b) - 4 to make a the subject
Angelina_Jolie [31]

Answer:

\boxed{a =  \frac{w}{ 6}  -  \frac{b}{2}  +  \frac{2}{3} }

Step-by-step explanation:

Solve  \: for \:  a:  \\  =  > w=3(2a+b)-4  \\  \\ w=3(2a+b)4 \: is \: equivalent \: to \: 3(2a+b)-4= w:  \\  =  > 3(2a+b) - 4=w  \\  \\ Expand \:  out \:  terms \:  of  \: the  \: left  \: hand \:  side:  \\  =  > (3 \times 2a) + (3 \times b) - 4 = w \\  =  > 6a+3b - 4=w  \\  \\ Subtract  \: 3b  - 4 \:  from  \: both \:  sides:  \\  =  >   6a + 3b - 4 - (3b - 4)=w - (3b - 4) \\   =  > 6a = w - 3b + 4 \\  \\ Divide  \: both  \: sides \:  by  \: 6: \\  =  >  \frac{ \cancel{6}a}{ \cancel{6}}  =  \frac{w - 3b + 4}{6}  \\   =  > a =  \frac{w}{6}  -  \frac{3b}{6}  +  \frac{4}{6}  \\  =  > a =  \frac{w}{ 6}  -  \frac{b}{2}  +  \frac{2}{3}

8 0
3 years ago
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