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andriy [413]
3 years ago
12

There are 12 state quarters and 4 regular quarters in a jar. Charles randomly picks a quarter and replaces it back in the jar. H

e then picks another quarter out of the jar. What is the probability that both are state quarters? Question 10 options: 16/9 1 9/16 24
Mathematics
1 answer:
melisa1 [442]3 years ago
3 0
64% I believe
Why?
Because 16:4 on quarters is 4:1 or 4/5 of the jar! Chances of you picking 4/5 is 80% so .80 x .80 =.64 or just over 3/5
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<u>Step-by-step explanation:</u>

When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:

(x-h)² + (y-k)² = r²    where

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1) Group the x's and y's together and move the number to the right side

   4x² - 16x         + 4y² - 24y               = -51        

2) Factor out the 4 from the x² and y²

    4(x² - 4x          ) + 4(y² - 6y            ) = -51

3) Complete the square (divide the x and y value by 2 and square it)

    4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)

  = 4(x - 2)² + 4(y - 3)² = -51 +  16  +  36

  = 4(x - 2)² + 4(y - 3)² = 1

4) Divide both sides by 4

   (x-2)^2+(y-3)^2=\dfrac{1}{4}

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