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siniylev [52]
2 years ago
11

Find the measure of GH.

Mathematics
2 answers:
Westkost [7]2 years ago
7 0

Answer:

D

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, then

The product of the external part and the whole secant is equal to the square of the tangent, that is

8(8 - 6 + 2x) = 12²

8(2 + 2x) = 144 ( divide both sides by 8 )

2 + 2x = 18 ( subtract 2 from both sides )

2x = 16 ( divide both sides by 2 )

x = 8

Then

GH = - 6 + 2x = - 6 + 2(8) = - 6 + 16 = 10 → D

Ierofanga [76]2 years ago
4 0

Answer:

\textsf{GH=10}

Step-by-step explanation:

(EF)^{2} =FG(FH)

(12)^{2} =8(8-6+2x)

144=8(2+2x)

144=16+16x

16x=144-16

16x=128

x=128/16=8

So, GH=-6+2(8)=

-6+16=

=10

\textsf{OAmalOHopeO}

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riadik2000 [5.3K]

900 ÷ 72 = 12.5 minutes

Thus the correct answer is option A .

7 0
2 years ago
What is the unknown term.<br>in the seqpence 4.5, 5.4,____7.2<br><br>A.6.2 or B. 63​
harina [27]

Answer:

6.3

Explanation:

To get from 4.5 to 5.4, you need to add 0.9. If you add 0.9 two more times, you get 7.2. Therefore, the middle term should be 6.3. I don't know if you made a typo and forgot the decimal when writing the options cause it says "63", but I believe the answer is 6.3.

4 0
3 years ago
Ok so math questions:
dolphi86 [110]
Joe: 24
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6 0
3 years ago
Dawg help meee !!!!!!
adelina 88 [10]

Answer:

The choice 4.

6 \sqrt{2x}

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I hope I helped you^_^

6 0
2 years ago
A dot-com company ships products from three different warehouses (A, B, and C). Based on customer complaints, it appears that 3%
Firlakuza [10]

Answer:

The probability of getting defective product from warehouse C is 0.3448

Step-by-step explanation:

<em>Missing question </em><em>"Assume that Ware houses A, B and C ship 30%, 20% and 50% of the dot-com's sales respectively.</em>

<em />

<em>P(A) = </em>Probability of product that comes from warehouse A

<em>P(B) = </em>Probability of product that comes from warehouse B

<em>P(C) = </em>Probability of product that comes from warehouse C

P(A) =  30% = 0.30, P(B) =  20% = 0.20, P(C) =  50% = 0.50

Let D denotes the number of defective products

P(D|A) = 3% = 0.03

P(D|B) = 5% = 0.05

P(D|C) = 2% = 0.02

The probability of getting defective product from warehouse C is as below using the Bayes Rule

P(C|D) = P(D|C) P(C) / P(D|A)P(A) + P(D|B)P(B) + P(D|C)P(C)

P(C|D) = 0.02 * 0.50 / (0.03*0.30) + (0.05*0.20) + (0.02*0.50)

P(C|D) = 0.01 / 0.009 + 0.01 + 0.01

P(C|D) = 0.01 / 0.029

P(C|D) = 0.3448

Therefore the probability of getting defective product from warehouse C is  0.3448.

3 0
3 years ago
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