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Aneli [31]
3 years ago
13

A rectangle measures 15 1/4 feet by 8 11/15 feet. If the length and width are extended by 1 2/3 Feet each find the area of the n

ew rectangle
Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

New area is 175 42/45 feet ²

Step-by-step explanation:

Given data

Length l= 15 1/4

To proper fraction = 61/4 feet

Width w= 8 11/15

To proper fraction = 131/15 feet

Extention = 1 2/3

To proper fraction = 5/3

Dimensions of new rectangle

Length =61/4+5/3 = 183+20/12

LCM = 12 = 203/12

Width = 131/15+5/3= 131+25/15

LCM = 15 = 156/15

Area = 203/12*156/15= =31668/180

=31668/180

= 7917/45

= 175 42/45 feet ²

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Answer:

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Step-by-step explanation:

ok so,

4 hours=240minutes

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so since one chore needs 40 minutes, then:

40/240= 6

so in 240 minutes/4 hours, Spencer can do 6 chores.

6 0
3 years ago
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The outer and inner triangles are both equilateral and the circle touches all three sides of the outer triangle. If the area of
Brrunno [24]

Answer:

The area of outer Δ = 40 cm²

Step-by-step explanation:

∵ Area of the small triangle = 10 cm²

If we join the center of the circle with the 3 vertices of the inner Δ

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Now the inner triangle has 3 isosceles Δ their sides are r , r and s1 with vertex angle 120° ⇒ (360° ÷ 3 = 120°)

Where r is the radius of the circle and s1 is the side of the inner triangle

<em>By using cosine rule</em>

(s1)² = r² + r² - 2r²cos120 = r² + r² - 2r² (-0.5) = r² + r² + r² = 3r²

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∵ The radius of the circle ⊥ to the side of the outer Δ because the side of the outer Δ is a tangent to the circle

If we join a vertex of the outer Δ with the center of the circle

We will have a right angle triangle of two legs r and half s2 with angle 60° (120° ÷ 2 )between them ⇒ s2 is the side of outer Δ

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∴ The side of the outer Δ is double the side of the inner Δ

<em>By using similarity ratio</em>

A2/A1 = (s2/s1)² ⇒ A2 and A1 are the areas of outer and inner triangles

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3 years ago
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The whole number is 10 the square root is 9
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AlexFokin [52]

Answer:

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:D I hope this helped you!

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