2x - 6y = 12
so we pick any number for x and then solve for y
lets say x = 0
2(0) - 6y = 12
-6y = 12
y = -12/6
y = -2....so when x = 0, y = -2....(0,-2) <== one point
lets say x = 1
2(1) - 6x = 12
2 - 6x = 12
-6x = 12 - 2
-6x = 10
x = -10/6
x = - 5/3...so when x = 1, y = -5/3....(1,-5/3) <== another point
Lets say x = 2
2(2) - 6y = 12
4 - 6y = 12
-6y = 12 - 4
-6y = 8
y = -8/6
y = - 4/3....so when x = 2, y = -4/3.....(2,-4/3) <== another point
lets say x = 3
2(3) - 6y = 12
6 - 6y = 12
-6y = 12 - 6
-6y = 6
y = -6/6
y = -1....so when x = 3, y = -1.....(3,-1) <== another point
now there is 4 points.
The answer is 53/6 in fraction form
D•2=32
D=16
Product is a quantity obtained by multiplying quantities together
Given the equation, 5x + 22 = 27:
The goal is to isolate the variable. Hence, a few mathematical operations are necessary to solve for the value of x.
Start by subtracting 22 both sides:
5x + 22 - 22 = 27 - 22
5x + 0 = 5
5x = 5
Next, divide both sides by 5 to isolate and solve for the value of x:
5x/5 = 5/5
x = 1
In order to verify whether x = 1 satisfies the give equation, we must substitute its value into the given equation:
5x + 22 = 27
5(1) + 22 = 27
5 + 22 = 27
27 = 27 (True statement. This implies that x = 1 is the correct value that satisfies the equation).
Therefore, the correct answer is x = 1.
